Two weak acid solutions `HA_(1)` and `HA_(2)` with the same concentration and having `pK_(a)` values 3 and 5 are placed in contact with hydrogen electrode `(1 atm ` and `25^(@)C)` and are interconnected through a salt bridge. Find the `EMF` of the cell.

Explanation

To find the EMF of the cell formed by two weak acid solutions \( HA_1 \) and \( HA_2 \) with given \( pK_a \) values, we can follow these steps:

### Step 1: Understand the dissociation of weak acids
Weak acids dissociate in water according to the following reaction:
\[ HA \rightleftharpoons H^+ + A^- \]
For each weak acid, we can express the acid dissociation constant \( K_a \) as:
\[ K_a = \frac{[H^+][A^-]}{[HA]} \]

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