Calculate the potential of silver electrode in a saturated solution of `AgBr(K_(sp)=6xx10^(-13))` containing `0.1 M KB r . E^(c-)._(Ag^(o+)|Ag)=0.80V.`

Explanation

To calculate the potential of the silver electrode in a saturated solution of AgBr, we will follow these steps:

### Step 1: Write the Dissociation Reaction and Ksp Expression
The dissociation of AgBr in water can be represented as:
\[ \text{AgBr (s)} \rightleftharpoons \text{Ag}^+ (aq) + \text{Br}^- (aq) \]

The solubility product constant (Ksp) expression for AgBr is:
\[ K_{sp} = [\text{Ag}^+][\text{Br}^-] \]
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