A solution of `Fe^(2+)` is titrated potentiaometrically using `Ce^(4+)` solution . Calculate the EMF of the oxidation electrode thus formed when
` 50%` of `Fe^(2+)` is titrated.
Fe2++Ce4+⇔Fe3++Ce3+

Explanation

To calculate the EMF of the oxidation electrode when 50% of `Fe^(2+)` is titrated with `Ce^(4+)`, we can follow these steps:

### Step 1: Write the half-reaction for the oxidation of `Fe^(2+)`
The oxidation reaction can be represented as follows:
\[ \text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + e^- \]

### Step 2: Set up the Nernst equation
The Nernst equation for the half-cell reaction is given by:
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