Home
Class 12
CHEMISTRY
Construct a cell using given electrodes ...

Construct a cell using given electrodes at `298K` and also calculate its standart `EMF`.
Given ` :` `E^(c-)._(Zn|Zn^(2+))=0.76V`
`E^(c-)._(Cu^(2+)|Cu)=0.34V`

Text Solution

Verified by Experts

At anode `:` `H_(2)hArr2H^(o+)+2e^(-)`
At cathode `:` `Zn^(2+)+2e^(-)hArrZn` `" "E=-0.46` volt
`[` negative value shows cell is not feasible `]`
`overlineunderline("Cell reaction:" H_(2)+Zn^(2+)hArrZn+2H^(o+))`
`E=E^(c-)-(0.059)/(2)log.([H^(o+)]^(2))/([Zn^(2+)])`
`=-0.46=-0.763-(0.059)/(2)log.([H^(o+)]^(2))/(0.3)`
Solve, `[H^(o+)]=4xx10^(-6)`
`HSO_(4)^(c-) rarr H^(o+)+SO^(4)^(2-)`
`K_(2)=([H^(+)][SO_(4)^(2-)])/([HSO_(4)^(c-)])=((4xx10^(-6))(6.44xx10^(-3)))/((0.4))`
`=6.44xx10^(-8)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples(Electrolysis And Electrolytic Cells)|12 Videos
  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 3.1 (Objective)|28 Videos
  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archieves Subjective|35 Videos
  • D AND F BLOCK ELEMENTS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|29 Videos
  • GENERAL PRINCIPLES AND PROCESS OF ISOLATION OF ELEMENTS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives (Subjective)|14 Videos

Similar Questions

Explore conceptually related problems

Calculate the maximum work that can be obtained from the decimolar Daniell cell at 25^(@)C . Given E^(c-)._((Zn^(2+)|Zn))=-0.76V and E^(c-)._((Cu^(2+)|Cu))=0.34V

If excess of Zn is added to 1.0M solution of CuSO_(4) , find the concentration of Cu^(2+) ions at equilibrium. Given :E^(c-)._((Zn^(2+)|Zn))=-0.76V E^(c-)._(cell)=(E^(c-)._((Cu^(2+)|Cu))=0.34V

(a) A cell is prepared by dipping a zinc rod in 1M zinc sulphate solution and a silver electrode in 1M silver nitrate solution. The standard electrode potential given : E^(@)Zn_(2+1//Zn) = -0.76V, E^(@)A_(g+//)A_(g) = +0.80V What is the effect of increase in concentration of Zn^(2+) " on the " E_(cell) ? (b) Write the products of electrolysis of aqueous solution of NaCI with platinum electrodes. (c) Calculate e.m.f. of the following cell at 298 K: "Ni(s)"//"Ni"^(2+)(0.01M)////"Cu"^(2+)(0.1M)//"Cu(s)" ["Given"E_(Ni2+//Ni)^(@) = -0.025 V E_(Cu2+//Cu)^(@) = +0.34V] Write the overall cell reaction.

For the cell : Zn (s) |Zn^(2+)(a M)||Ag^(o+)(bM)|Ag(s) . a. Write Nernst equation to show how E_(cell) vary with concentration of Zn^(2+) and Ag^(o+) ions. Given E^(c-)._((Zn^(2+)|Zn))=0.76V,E^(-)._((Ag^(o+)|Ag))=0.80V. b. Find E_(cell) for [Zn^(2+)]=0.01M and [Ag^(c-)]=0.02M . c. For what values of Q will the cell EMF be i. 0.0V" "ii. 0.97 V

Can a solution of 1 M ZnSO_(4) be stored in a vessel made of copper ? Given that E_(Zn^(+2)//Zn)^(@) =-0.76V and E_(Cu^(+2)//Cu)^(@)=0.34 V

The following electrochemical cell is set up at 298 K: Zn//Zn^(2+) (aq) (1 M) || Cu^(2+) (aq) (1 M)//Cu Given: E^(@)Zn^(2+)//Zn =-0.761 V, E^(@) Cu^(2+)//Cu=+0.339 V (1) Write the cell reaction. (2) Calculate the emf and free energy change at 298 K

Calculate the emf of the given cell: Cu/ Cu^(2+)(0.01M) ∣∣ Cu^(2+) (0.001M)∣Cu is ( E^(@)Cu^(2+) /Cu=+0.34V)

Which of the following will act as cathode when connected to standard hydrogen electrode which has E^(@) value given as zero ? (i) Zn^(2+)//Zn, E^(@)=-0.76V (ii) Cu^(2+)//Cu, E^(@)=+0.34 V (iii) Al^(3+)//Al, E^(@)=-1.66 V (iv) Hg^(2+)//Hg, E^(@)=+0.885 V (A)(i) and (ii) (B)(ii) and (iv) (C)(i) and (iii) (D)(i), (ii), (iii) and (iv)

Copper from copper sulphate solution can be displacesd by. (The standard reduction potentials of some electrodes are given below): E^(o)(Fe^(2+)//Fe) = - 0.44 V, E^(o) (Zn^(2+)//Zn) = - 0.76 V E^(o) (Cu^(2+)//Cu) = + 0.34 V: E^(o)(Cr^(3+)//Cr) = - 0.74 V E^(o) (H^(+)// 1/2H_(2)) = 0.00V

Calculate the quantity of electricity dellvered by a Daniel celi initially containing 1 L each of 1M Cu^(2+) ion and 1M Zn^(2+) C which is operated until potential drops to 1V. Given E^(@) Zn^(2+)//Zn=-0.76V, E_(Cu^(2+)//Cu)^(@)=+0.34V

CENGAGE CHEMISTRY ENGLISH-ELECTROCHEMISTRY-Solved Examples (Electrochemical Cell)
  1. The EMF of the cell : Ag|Ag(2)CrO(4)(s),K(2)CrO(4)(0.1 M)||AgNO(3)(0...

    Text Solution

    |

  2. The EMF of a galvanic cell Pt|H(2)(1 atm)|HCl(1M)|Cl(2)(g)|Pt is 1.29V...

    Text Solution

    |

  3. Calculate the potential of silver electrode in a saturated solution of...

    Text Solution

    |

  4. A solution of Fe^(2+) is titrated potentiaometrically using Ce^(4+) so...

    Text Solution

    |

  5. Find the EMF of the cell at 25^(@)C. E^(c-).(red("quinhydrone elec...

    Text Solution

    |

  6. Construct a cell using given electrodes at 298K and also calculate its...

    Text Solution

    |

  7. The EMF of the following cell is observed to be 0.118V at 25^(@)C: ...

    Text Solution

    |

  8. Find the standard electrode potential of I(2)|2I^(c-) if the equilibri...

    Text Solution

    |

  9. A silver electrode dipping in AgNO(3) solution (0.1M) is combined salt...

    Text Solution

    |

  10. The EMF of a galvanic cell composed of two hydrogen electrodes is 177 ...

    Text Solution

    |

  11. The EMF of the cell : Pt|Ce^(4+)(90%),Ce^(3+)(10%)| Normal calomel...

    Text Solution

    |

  12. A hydrogen electrode placed in a buffer solution of sodium cyanide and...

    Text Solution

    |

  13. Two electrochemical cells are assembled in which the following reactio...

    Text Solution

    |

  14. Predict whether or not Cl(2) would disproportionate in cold alkaline m...

    Text Solution

    |

  15. What would be the electrode potential of a silver electrode dipped in ...

    Text Solution

    |

  16. E^(c-) of some elements are given as : {:(I(2)+2e^(-)rarr 2I^(c-),,,...

    Text Solution

    |

  17. Select the spontaneous rreactions from the changes given below a. Sn...

    Text Solution

    |

  18. Two metals M(1) and M(2) have E^(c-).(red)=-0.76 V and 0.80V, respecti...

    Text Solution

    |

  19. Determine whether O(2)(g) can oxidize sulphate (SO(4)^(2-)) ion to pe...

    Text Solution

    |

  20. Quinones are good electron acceptors, party because reduction restores...

    Text Solution

    |