A hydrogen electrode placed in a buffer solution of sodium cyanide and `HCN` in the ration of `x:y` and `y:x` has electrode potential value `a` and `b` volts, respectively, at `25^(@)C`. If the difference `a-b=35.52mV, ` what is the ratio of `y:x.`

Explanation

To solve the problem, we need to find the ratio \( \frac{y}{x} \) given the electrode potentials \( a \) and \( b \) for two different buffer solutions of sodium cyanide and hydrogen cyanide. Let's break down the solution step by step.

### Step 1: Understand the relationship between pH and electrode potential
For a buffer solution, the pH is given by the Henderson-Hasselbalch equation:
\[ \text{pH} = \text{pK}_a + \log\left(\frac{\text{[Salt]}}{\text{[Acid]}}\right) \]
For the first solution with the ratio \( x:y \):
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