During an electrolysis of conc `H_(2)SO_(4)` , perdisulphuric acid `(H_(2)S_(2)_(8))` and `O_(2)` are formed in equimolar amount. The moles of `H_(2)` that will be formed simultaneously will be
`a. `Thrice that of `O_(2)" "b.` Twice that of `O_(2)`
`c.` Equal to that of `O_(2)." "d.` Half of that of `O_(2)`

Explanation

To solve the problem, we need to analyze the electrolysis of concentrated sulfuric acid (H₂SO₄) and determine the relationship between the moles of hydrogen gas (H₂) and oxygen gas (O₂) produced during the process.

### Step-by-Step Solution:

1. **Identify the Electrolysis Reaction**:
- During the electrolysis of concentrated H₂SO₄, perdisulfuric acid (H₂S₂O₈) and oxygen (O₂) are formed. The overall reaction can be represented as:
\[
2 \text{H}_2\text{SO}_4 \rightarrow \text{H}_2\text{S}_2\text{O}_8 + \text{O}_2 + \text{H}_2
...