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Which of the following changes will incr...

Which of the following changes will increase the `EMF` of the cell `:`
`Co(s)|CoCl_(2)(M_(2))||HCl(M_(2))||(H_(2),g)Pt`

A

Increase the volume of `CoCl_(2)` from `100mL` to `200mL`

B

Increase `M_(2)` from `0.1 M` to `0.50M`.

C

Increase the pressure of the `H_(2)(g)` from `1.0` to `2.0 atm`.

D

Increase `M_(1)` from `0.01M` to `0.50M`.

Text Solution

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The correct Answer is:
To determine which changes will increase the EMF of the cell represented by the notation `Co(s)|CoCl_(2)(M_(2))||HCl(M_(2))||(H_(2),g)Pt`, we can analyze the effects of each proposed change on the EMF using the Nernst equation. ### Step-by-Step Solution: 1. **Identify the Cell Reaction**: - The cell reaction involves cobalt being oxidized and hydrogen ions being reduced. The overall reaction can be represented as: \[ Co(s) \rightarrow Co^{2+}(aq) + 2e^{-} \quad \text{(oxidation)} \] \[ 2H^{+}(aq) + 2e^{-} \rightarrow H_{2}(g) \quad \text{(reduction)} \] 2. **Write the Nernst Equation**: - The Nernst equation for this cell can be expressed as: \[ E_{cell} = E^{\circ} - \frac{0.0592}{n} \log \left( \frac{[Co^{2+}]}{[H^{+}]^2 \cdot P_{H_{2}}} \right) \] - Here, \( n = 2 \) (the number of electrons transferred). 3. **Analyze Each Change**: - **Change A**: Increasing the volume of CoCl₂ from 100 mL to 200 mL. - Increasing the volume decreases the concentration of \( Co^{2+} \) ions, which will increase the EMF since it appears in the numerator of the log term. - **Conclusion**: This change will increase EMF. - **Change B**: Increasing \( M_2 \) (the concentration of \( H^+ \)) from 0.1 M to 0.5 M. - Increasing \( H^+ \) concentration decreases the denominator in the Nernst equation, which will also increase EMF. - **Conclusion**: This change will increase EMF. - **Change C**: Increasing the pressure of hydrogen gas from 1 atm to 2 atm. - Increasing the pressure of \( H_2 \) increases the concentration of \( H_2 \) in the numerator, which will decrease EMF. - **Conclusion**: This change will not increase EMF. - **Change D**: Increasing \( M_1 \) (the concentration of \( Co^{2+} \)) from 0.01 M to 0.5 M. - Increasing \( Co^{2+} \) concentration increases the numerator in the Nernst equation, which will decrease EMF. - **Conclusion**: This change will not increase EMF. 4. **Final Answer**: - The changes that will increase the EMF of the cell are: - **Change A**: Increasing the volume of CoCl₂ from 100 mL to 200 mL. - **Change B**: Increasing \( M_2 \) from 0.1 M to 0.5 M. ### Summary: The correct options that will increase the EMF of the cell are **A and B**. ---

To determine which changes will increase the EMF of the cell represented by the notation `Co(s)|CoCl_(2)(M_(2))||HCl(M_(2))||(H_(2),g)Pt`, we can analyze the effects of each proposed change on the EMF using the Nernst equation. ### Step-by-Step Solution: 1. **Identify the Cell Reaction**: - The cell reaction involves cobalt being oxidized and hydrogen ions being reduced. The overall reaction can be represented as: \[ Co(s) \rightarrow Co^{2+}(aq) + 2e^{-} \quad \text{(oxidation)} ...
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