During electrolysis of aqueous `CuBr_(2)` using `Pt` electrode,

Options

A. `Br_(2)(g)` is evolved at anode
B. `Cu(s)` is deposited at cathdoe
C. `Br_(2)(g)` is evolved at anode and `H_(2)(g)` at cathode
D. `H_(2)(g)` is evolved at anode

Explanation

To solve the problem of electrolysis of aqueous \( \text{CuBr}_2 \) using a platinum electrode, we will analyze the reactions occurring at both the anode and cathode.

### Step 1: Identify the Electrolyte and Its Components
The electrolyte in this case is aqueous \( \text{CuBr}_2 \). It dissociates into \( \text{Cu}^{2+} \) ions and \( \text{Br}^{-} \) ions in solution:
\[ \text{CuBr}_2 \rightarrow \text{Cu}^{2+} + 2\text{Br}^{-} \]

**Hint:** Remember that the ions present in the solution will determine the reactions that occur during electrolysis.

### Step 2: Determine the Reaction at the Cathode
At the cathode, reduction occurs. The \( \text{Cu}^{2+} \) ions gain electrons to form solid copper:
\[ \text{Cu}^{2+} + 2e^{-} \rightarrow \text{Cu (s)} \]

**Hint:** At the cathode, look for the species that can gain electrons.

### Step 3: Determine the Reaction at the Anode
At the anode, oxidation occurs. The \( \text{Br}^{-} \) ions lose electrons to form bromine gas:
\[ 2\text{Br}^{-} \rightarrow \text{Br}_2 (g) + 2e^{-} \]

**Hint:** At the anode, identify the species that can lose electrons.

### Step 4: Analyze the Options
Now, let's evaluate the options provided in the question:

1. **Option A:** \( \text{Br}_2 \) gaseous is evolved at the anode.
- This is correct because bromine gas is produced at the anode.

2. **Option B:** Copper solid is deposited at the cathode.
- This is correct because solid copper is deposited at the cathode.

3. **Option C:** \( \text{Br}_2 \) gaseous is evolved at the anode and \( \text{H}_2 \) at the cathode.
- This is incorrect because only \( \text{Cu} \) is deposited at the cathode, not \( \text{H}_2 \).

4. **Option D:** \( \text{H}_2 \) gas is evolved at the anode.
- This is incorrect because \( \text{H}_2 \) is not produced at the anode; \( \text{Br}_2 \) is produced instead.

### Conclusion
Based on the analysis, the correct options are:
- Option A: \( \text{Br}_2 \) gaseous is evolved at anode (Correct)
- Option B: Copper solid is deposited at cathode (Correct)

**Final Answer:** Options A and B are correct.