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During discharging of alead storage batt...

During discharging of alead storage battery

A

The reaction at anode is `Pb rarr Pb^(2+)+2e^(-)`

B

The reaction taking place at cathode is
`Pb^(2+)+2e^(-) rarr Pb`

C

The overall reaction is
`Pb+PbO_(2)+4H^(o+) +2SO_(4)^(2-) rarr 2PbSO_(4)+2H_(2)O`

D

The reaction taking place at cathode is
`PbO_(2)+4H^(o+)+2e^(-) rarr Pb^(2+)+2H_(2)O`

Text Solution

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The correct Answer is:
To solve the question regarding the discharging of a lead storage battery, we will analyze the reactions occurring at the anode and cathode, and then evaluate each of the provided options. ### Step-by-Step Solution: 1. **Identify the Reactions at the Anode and Cathode:** - **At the Anode (Oxidation):** - The reaction involves lead (Pb) solid losing electrons to form lead(II) sulfate (PbSO4). - Reaction: \[ \text{Pb (s)} + \text{SO}_4^{2-} \rightarrow \text{PbSO}_4 + 2e^- \] - **At the Cathode (Reduction):** - The reaction involves lead(IV) oxide (PbO2) gaining electrons and reacting with hydrogen ions (H+) and sulfate ions (SO4^2-) to form lead(II) sulfate (PbSO4) and water (H2O). - Reaction: \[ \text{PbO}_2 + 4\text{H}^+ + \text{SO}_4^{2-} + 2e^- \rightarrow \text{PbSO}_4 + 2\text{H}_2\text{O} \] 2. **Determine the Oxidation States:** - **At the Anode:** - Lead (Pb) goes from an oxidation state of 0 (in solid form) to +2 (in PbSO4). - **At the Cathode:** - Lead (Pb) in PbO2 has an oxidation state of +4 and is reduced to +2 in PbSO4. 3. **Evaluate Each Option:** - **Option 1:** "The reaction at anode is Pb is converted to Pb2+." - This is correct, as Pb is indeed oxidized to Pb2+. - **Option 2:** "The reaction taking place at cathode is Pb2+ gains 2 electrons and converted to Pb." - This is incorrect; PbO2 (with +4 oxidation state) is reduced, not Pb2+. - **Option 3:** "Overall reaction is Pb + PbO2 + 4H+ + 2SO4^2- gives 2PbSO4 + 2H2O." - This is correct, as it represents the net reaction accurately. - **Option 4:** "The reaction taking place at cathode is PbO2 + 4H+ + 2 electrons gives Pb2+ + 2H2O." - This is incorrect; the product is PbSO4, not Pb2+. ### Final Summary: - **Correct Options:** 1 and 3 - **Incorrect Options:** 2 and 4

To solve the question regarding the discharging of a lead storage battery, we will analyze the reactions occurring at the anode and cathode, and then evaluate each of the provided options. ### Step-by-Step Solution: 1. **Identify the Reactions at the Anode and Cathode:** - **At the Anode (Oxidation):** - The reaction involves lead (Pb) solid losing electrons to form lead(II) sulfate (PbSO4). - Reaction: ...
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