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Assertion (A) : In a Daniell cell, if th...

Assertion `(A) :` In a Daniell cell, if the concentration of `Cu^(2+)` and `Zn^(2+)` ions are doubled, the `EMF` of the cell will be doubled.
Reason `(R) :` If the concentration of ions in contact with metals is doubled, the electrode potential is doubled.
(a)If both `(A)` and `(R)` are correct, and `(R)` is the correct explanation of `(A)`.
(b)If both `(A)` and `(R)` are correct, but `(R)` is not the correct explanation of `(A)`.
(c)If `(A)` is correct, but `(R)` is incorrect.
(d)If `(A)` is incorrect, `(R)` is correct.

A

If both `(A)` and `(R)` are correct, and `(R)` is the correct explanation of `(A)`.

B

If both `(A)` and `(R)` are correct, but `(R)` is not the correct explanation of `(A)`.

C

If `(A)` is correct, but `(R)` is incorrect.

D

If `(A)` is incorrect, `(R)` is correct.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion (A) and the reason (R) provided. ### Step 1: Understanding the Assertion (A) The assertion states that in a Daniell cell, if the concentration of `Cu^(2+)` and `Zn^(2+)` ions are doubled, the EMF of the cell will also be doubled. **Analysis**: - The EMF (Electromotive Force) of a Daniell cell is determined by the Nernst equation, which states that the EMF is dependent on the concentration of the ions involved in the redox reaction. - Specifically, the EMF is proportional to the difference in the electrode potentials of the two half-cells. - If both concentrations are doubled, the ratio of the concentrations remains constant (since both the numerator and denominator are multiplied by the same factor). - Therefore, the EMF does not change; it remains constant. ### Conclusion for Assertion (A): **Assertion (A) is incorrect.** ### Step 2: Understanding the Reason (R) The reason states that if the concentration of ions in contact with metals is doubled, the electrode potential is doubled. **Analysis**: - The electrode potential of a half-cell is indeed affected by the concentration of the ions in contact with the electrode, as described by the Nernst equation. - If the concentration of the ions is doubled, the electrode potential will increase, but it does not necessarily mean it will double. It depends on the specific half-reaction and the conditions. - Therefore, while the statement is partially correct, it is misleading because it implies a direct doubling of potential, which is not universally true. ### Conclusion for Reason (R): **Reason (R) is incorrect.** ### Final Conclusion: Since assertion (A) is incorrect and reason (R) is also incorrect, the correct answer is: **(d) If (A) is incorrect, (R) is correct.**
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