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Balance the following reaction by H & T ...

Balance the following reaction by H & T method: Zn + HCl = ZnCl2 + H2

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To balance the reaction \( \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \) using the H & T (Hit and Trial) method, follow these steps: ### Step 1: Write down the unbalanced equation The initial unbalanced equation is: \[ \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] ### Step 2: List the number of atoms of each element Count the number of atoms for each element on both sides of the equation. - **Left Side (Reactants):** - Zn: 1 - H: 1 - Cl: 1 - **Right Side (Products):** - Zn: 1 - H: 2 - Cl: 2 ### Step 3: Identify which elements are unbalanced From the counts: - Zinc (Zn) is balanced (1 on both sides). - Hydrogen (H) is unbalanced (1 on the left, 2 on the right). - Chlorine (Cl) is unbalanced (1 on the left, 2 on the right). ### Step 4: Balance the hydrogen and chlorine To balance the hydrogen, we can adjust the coefficient of HCl on the left side. Since there are 2 hydrogen atoms on the right side, we need to have 2 HCl on the left side. So, we change the equation to: \[ \text{Zn} + 2 \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] ### Step 5: Recount the atoms Now, let's recount the atoms: - **Left Side (Reactants):** - Zn: 1 - H: 2 (from 2 HCl) - Cl: 2 (from 2 HCl) - **Right Side (Products):** - Zn: 1 - H: 2 - Cl: 2 ### Step 6: Confirm that all elements are balanced Now, all elements are balanced: - Zn: 1 on both sides - H: 2 on both sides - Cl: 2 on both sides ### Final Balanced Equation The balanced equation is: \[ \text{Zn} + 2 \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] ---

To balance the reaction \( \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \) using the H & T (Hit and Trial) method, follow these steps: ### Step 1: Write down the unbalanced equation The initial unbalanced equation is: \[ \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] ### Step 2: List the number of atoms of each element Count the number of atoms for each element on both sides of the equation. ...
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