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Tollen reagent is used for the detection...

Tollen reagent is used for the detection of aldehydes. When a solution of `AgNO_(3)` is added to glucose with `NH_(4)OH`, then gluconic acid is formed.
`Ag^(o+)+e^(-) rarr Ag," "E^(c-)._(red)=0.8V`
`C_(6)H_(12)O_(6)rarr underset(Gluconic aci d)(C_(6)H_(12)O_(7)+)2H^(o+)+2e^(-) , " "E^(c-)._(o x i d ) =-0.05V`
`[Ag(NH_(3))_(2)]^(o+)+e^(-) rarr Ag(s)+2NH_(3), " "E^(c-)._(red)=0.337V`
`[Use2.303xx(RT)/(F)=0.0592` and `(F)/(RT)=38.92at 298 K ]`
Ammonia is always added in this reaction. Which of the following must be correct ?
(a)`NH_(3)` combines with `Ag^(o+)` to form a complex.
(b)`[Ag(NH_(3))_(2)]^(o+)` is a stronger oxidizing reagent than `Ag^(o+)`
(c)Both a and b
(d)None of these

A

`NH_(3)` combines with `Ag^(o+)` to form a complex.

B

`[Ag(NH_(3))_(2)]^(o+)` is a stronger oxidizing reagent than `Ag^(o+)`

C

Both a and b

D

None of these

Text Solution

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The correct Answer is:
To solve the question, we need to analyze the statements regarding the reactions involving Tollen's reagent, which is a complex of silver ions with ammonia, and its role in detecting aldehydes. ### Step-by-Step Solution: 1. **Understanding Tollen's Reagent**: Tollen's reagent is a solution of silver nitrate (\(AgNO_3\)) in ammonia (\(NH_3\)). It is used to detect aldehydes, which can reduce silver ions to metallic silver. 2. **Formation of Silver Ammonia Complex**: When ammonia is added to silver nitrate, it forms a complex ion \([Ag(NH_3)_2]^+\). This indicates that ammonia acts as a ligand and coordinates to the silver ion. 3. **Analyzing Statement (a)**: The first statement claims that \(NH_3\) combines with \(Ag^+\) to form a complex. This is true because the formation of \([Ag(NH_3)_2]^+\) is a well-known reaction in coordination chemistry. 4. **Analyzing Statement (b)**: The second statement claims that \([Ag(NH_3)_2]^+\) is a stronger oxidizing agent than \(Ag^+\). To evaluate this, we compare their standard reduction potentials: - For \(Ag^+\): \(E^{\circ}_{red} = 0.8 \, V\) - For \([Ag(NH_3)_2]^+\): \(E^{\circ}_{red} = 0.337 \, V\) A higher reduction potential indicates a stronger oxidizing agent. Since \(0.8 \, V\) (for \(Ag^+\)) is greater than \(0.337 \, V\) (for the complex), \(Ag^+\) is a stronger oxidizing agent than \([Ag(NH_3)_2]^+\). Therefore, this statement is false. 5. **Conclusion**: - Statement (a) is true. - Statement (b) is false. - Therefore, the correct answer is (a) \(NH_3\) combines with \(Ag^+\) to form a complex. ### Final Answer: **(a)** \(NH_3\) combines with \(Ag^+\) to form a complex.

To solve the question, we need to analyze the statements regarding the reactions involving Tollen's reagent, which is a complex of silver ions with ammonia, and its role in detecting aldehydes. ### Step-by-Step Solution: 1. **Understanding Tollen's Reagent**: Tollen's reagent is a solution of silver nitrate (\(AgNO_3\)) in ammonia (\(NH_3\)). It is used to detect aldehydes, which can reduce silver ions to metallic silver. 2. **Formation of Silver Ammonia Complex**: ...
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Tollen reagent is used for the detection of aldehydes. When a solution of AgNO_(3) is added to glucose with NH_(4)OH , then gluconic acid is formed. Ag^(o+)+e^(-) rarr Ag," "E^(c-)._(red)=0.8V C_(6)H_(12)O_(6)rarr underset(Gluconic aci d)(C_(6)H_(12)O_(7)+)2H^(o+)+2e^(-) , " "E^(c-)._(o x i d ) =-0.05V [Ag(NH_(3))_(2)]^(o+)+e^(-) rarr Ag(s)+2NH_(3), " "E^(c-)._(red)=0.337V [Use2.303xx(RT)/(F)=0.0592 and (F)/(RT)=38.92at 298 K ] When ammonia is added to the solution, pH is raised to 11 . Which half cell reaction is affected by pH and by how much ?

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