The decompoistion of ammonia on platinum surface follows the change
`2NH_(3) rarr N_(2) + 3H_(2)`
If the decomposition is zero order then what are the rates of Production of `N_(2)` and `H_(2)` if `k = 2.5 xx 10^(-4) M s^(-1)` ?

Explanation

To solve the problem of the decomposition of ammonia on a platinum surface, we need to determine the rates of production of nitrogen (N₂) and hydrogen (H₂) given that the reaction is zero-order and the rate constant (k) is \(2.5 \times 10^{-4} \, \text{M s}^{-1}\).

### Step-by-Step Solution:

1. **Identify the Reaction**: The decomposition of ammonia is given by the equation:
\[ 2 \text{NH}_3 \rightarrow \text{N}_2 + 3 \text{H}_2 \]
...