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The forward reaction rate for the nitric...

The forward reaction rate for the nitric oxide-oxygen reaction
`2NO+O_(2) rarr 2NO_(2)` has the rate law as:
`Rate = k[NO]^(2)[O_(2)]`.
If the mechanism is assumed to be:
`2NO+O overset(k_(eq))hArr` , (rapid equilibration)
`N_(2)O_(2) + O_(2) overset(k_(2))rarr 2NO_(2)` (slow step),
then which of the following is (are) correct?
(I) Rate constant `= k_(eq)k_(2)` , (II) `[N_(2)O_(2)] = k_(eq)[NO]^(2)`
(III) `[N_(2)O_(2)] = k_(eq)[NO]` , (IV) Rate constant `= k_(2)`
The correct option is

A

I, II

B

III, IV

C

I, III

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the given reaction mechanism and the rate law provided. The reaction is: \[ 2NO + O_2 \rightarrow 2NO_2 \] with the rate law: \[ \text{Rate} = k[NO]^2[O_2] \] The proposed mechanism is: 1. \( 2NO + O \overset{k_{eq}}{\rightleftharpoons} N_2O_2 \) (rapid equilibrium) 2. \( N_2O_2 + O_2 \overset{k_2}{\rightarrow} 2NO_2 \) (slow step) ### Step 1: Understanding the Equilibrium Step The first step is an equilibrium step, which means that we can express the equilibrium constant \( k_{eq} \) as: \[ k_{eq} = \frac{[N_2O_2]}{[NO]^2} \] From this, we can rearrange to find the concentration of \( N_2O_2 \): \[ [N_2O_2] = k_{eq} [NO]^2 \] ### Step 2: Rate of the Slow Step The second step is the slow step and is the rate-determining step. The rate of this step can be expressed as: \[ \text{Rate} = k_2 [N_2O_2][O_2] \] ### Step 3: Substituting for \( [N_2O_2] \) Now, we substitute the expression for \( [N_2O_2] \) from Step 1 into the rate expression from Step 2: \[ \text{Rate} = k_2 (k_{eq} [NO]^2)[O_2] \] This simplifies to: \[ \text{Rate} = k_2 k_{eq} [NO]^2 [O_2] \] ### Step 4: Identifying the Overall Rate Constant From the derived rate expression, we can identify the overall rate constant \( k \): \[ k = k_2 k_{eq} \] ### Step 5: Evaluating the Options Now we can evaluate the options given in the question: 1. **(I) Rate constant \( = k_{eq} k_2 \)**: This is correct as derived above. 2. **(II) \( [N_2O_2] = k_{eq} [NO]^2 \)**: This is also correct as derived from the equilibrium expression. 3. **(III) \( [N_2O_2] = k_{eq} [NO] \)**: This is incorrect; it should be \( [N_2O_2] = k_{eq} [NO]^2 \). 4. **(IV) Rate constant \( = k_2 \)**: This is incorrect; the rate constant is \( k_2 k_{eq} \). ### Conclusion The correct options are (I) and (II).

To solve the problem, we will analyze the given reaction mechanism and the rate law provided. The reaction is: \[ 2NO + O_2 \rightarrow 2NO_2 \] with the rate law: \[ \text{Rate} = k[NO]^2[O_2] \] ...
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