Home
Class 12
CHEMISTRY
Gaseous cyclobutane isomerizes to butadi...

Gaseous cyclobutane isomerizes to butadiene in a first order process which has `k` value at `153^(@)C` of `3.3 xx 10^(-4) s^(-1)`. How many minutes would it take for the isomerization to proceeds `40%` to completion at this temperature ?

A

`A. 26 min`

B

`B. 52 min`

C

`C. 13 min`

D

D. None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how long it takes for gaseous cyclobutane to isomerize to butadiene, we will use the first-order kinetics formula. Here’s a step-by-step breakdown: ### Step 1: Understand the Reaction The reaction is a first-order process, and we are given that cyclobutane is isomerizing to butadiene. We need to find out how long it takes for the reaction to proceed 40% to completion. ### Step 2: Define Initial and Final Concentrations - Initial concentration of cyclobutane, \( [A_0] = 100\% \) - After 40% completion, the remaining concentration of cyclobutane, \( [A] = 100\% - 40\% = 60\% \) ### Step 3: Use the First-Order Rate Equation The first-order rate equation is given by: \[ k = \frac{2.303}{t} \log\left(\frac{[A_0]}{[A]}\right) \] Where: - \( k = 3.3 \times 10^{-4} \, \text{s}^{-1} \) - \( [A_0] = 100 \) - \( [A] = 60 \) ### Step 4: Substitute Values into the Equation Substituting the values into the equation: \[ 3.3 \times 10^{-4} = \frac{2.303}{t} \log\left(\frac{100}{60}\right) \] ### Step 5: Calculate the Logarithm Calculate the logarithm: \[ \frac{100}{60} = \frac{5}{3} \] Now, calculate \( \log\left(\frac{5}{3}\right) \): \[ \log\left(\frac{5}{3}\right) = \log(5) - \log(3) \] Using known logarithm values: - \( \log(5) \approx 0.6990 \) - \( \log(3) \approx 0.4771 \) Thus, \[ \log\left(\frac{5}{3}\right) \approx 0.6990 - 0.4771 = 0.2219 \] ### Step 6: Rearranging to Find Time \( t \) Now, substitute back into the equation: \[ 3.3 \times 10^{-4} = \frac{2.303}{t} \times 0.2219 \] Rearranging gives: \[ t = \frac{2.303 \times 0.2219}{3.3 \times 10^{-4}} \] ### Step 7: Calculate \( t \) Calculating \( t \): \[ t = \frac{0.5115}{3.3 \times 10^{-4}} \approx 1549.0 \, \text{s} \] ### Step 8: Convert Seconds to Minutes To convert seconds to minutes: \[ \text{Minutes} = \frac{1549.0}{60} \approx 25.8 \, \text{minutes} \] ### Final Answer Thus, it would take approximately **26 minutes** for the isomerization to proceed 40% to completion. ---

To solve the problem of how long it takes for gaseous cyclobutane to isomerize to butadiene, we will use the first-order kinetics formula. Here’s a step-by-step breakdown: ### Step 1: Understand the Reaction The reaction is a first-order process, and we are given that cyclobutane is isomerizing to butadiene. We need to find out how long it takes for the reaction to proceed 40% to completion. ### Step 2: Define Initial and Final Concentrations - Initial concentration of cyclobutane, \( [A_0] = 100\% \) - After 40% completion, the remaining concentration of cyclobutane, \( [A] = 100\% - 40\% = 60\% \) ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 4.3 More Than One Correct|5 Videos
  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex4.4 Objective|10 Videos
  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 4.2 (Objective)|10 Videos
  • CARBOXYLIC ACIDS AND THEIR DERIVATIVES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Analytical And Descriptive)|34 Videos
  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|18 Videos

Similar Questions

Explore conceptually related problems

Gasesous cyclobutane isomerizes to butadiene following first order process which has half life of 150.5 minute at certain temperature. How long will take for the process to occur to the extent of 40% at the same temperature ?

A first order reaction has a specific reaction rate of 10^(-2) s^(-1) . How much time will it take for 20 g of the reactant to reduce to 5 g ?

A first order reaction has a rate constant of 1.15 xx 10^(-3) s^(-1) How long will 5 g of this reactant take to reduce to 3g?

A first order reaction has specific reaction rate of 10^(-3) s^(-1) . How much time will it takes for 10 gm of the reactant to reduce to 2.5 gm ?

A first order reaction has a specific rate constant of 2xx10^(-3)s^(-1) . How much time it will take for20 gm to reduce to 5 g ?

A first order reaction has specific rate of 10^(-2)s^(-1) . How much time will it take for 20 g of the reactant to reduce to 5 g?

A first order reaction is 50% completed in 1.26 xx 10^(14) s. How much time would it take for 100% completion ?

A first order reaction has a rate constant of 5 xx 10^(-3) s^(-1) . How long will 5.0 g of this reaction take to reduce to 3.0 g ?