The inverison of cane sugar is a……………reaction though its molecularity is………………. .

Answer

To solve the question regarding the inversion of cane sugar, we need to analyze the reaction and determine its characteristics in terms of order and molecularity.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
The inversion of cane sugar (sucrose) involves its hydrolysis in the presence of water, resulting in the formation of glucose and fructose. The chemical equation for this reaction can be written as:
\[ \text{C}_{12}\text{H}_{22}\text{O}_{11} + \text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + \text{C}_6\text{H}_{12}\text{O}_6 \]
Here, sucrose reacts with water to produce glucose and fructose.

2. **Identifying the Order of Reaction**:
The order of a reaction is determined by the concentration of the reactants that affect the rate of the reaction. In this case, since water is in excess, the rate of reaction is primarily dependent on the concentration of sucrose. Therefore, the order of the reaction with respect to sucrose is 1.

3. **Determining the Molecularity**:
Molecularity refers to the number of reactant molecules that are involved in the rate-determining step of the reaction. In this case, we have:
- 1 molecule of sucrose (C₁₂H₂₂O₁₁)
- 1 molecule of water (H₂O)

Thus, the total molecularity of the reaction is:
\[ \text{Molecularity} = 1 + 1 = 2 \]

4. **Conclusion**:
Based on the analysis, we can conclude that the inversion of cane sugar is a **first-order reaction** with respect to sucrose, and its **molecularity is 2**.

### Final Answer:
The inversion of cane sugar is a **first-order reaction** though its molecularity is **2**.

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