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The rate law for the reaction, RCl+NaOH...

The rate law for the reaction, `RCl+NaOH(aq)rarrROH +NaCl` is given by Rate =k[RCl] The rate of reaction will be

A

Doubled by doubling the concentration of `NaOH`

B

Halved by reducing the concentration of `RCl` by one half

C

Increased by increaisng the temperature of the reaction.

D

Unaffected by change of temperature

Text Solution

Verified by Experts

The correct Answer is:
B, C
(a) Rate is independent of `[NaOH]`, hence wrong.
(b) Correct rate `prop [RCl]`.
( c) Correct rate `prop T`.
(d) Wrong.
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