How many moles of helium are produced when 1 mole of `._(92)U^(238)` disintegrate into `._(82)Pb^(206)`?

Explanation

To solve the problem of how many moles of helium are produced when 1 mole of Uranium-238 disintegrates into Lead-206, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the decay process**: Uranium-238 (U-238) undergoes alpha decay. In this process, it emits alpha particles, which are essentially helium nuclei (He-4).

2. **Determine the change in atomic and mass numbers**:
- The atomic number of U-238 is 92, and its mass number is 238.
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