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In the given radioactive disintegration ...

In the given radioactive disintegration series,
`._90^(232)Th to _(2)^(208)Pb`
Calculate value of `(n+2)`.
Where value of n is number of isobars formed in this series, suppose there is successive emission of `beta-`particles.

Text Solution

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Parent element =`._(92)U^(238)`, daughter element =`._(82)Pb^(206)`. Let `x alpha-` and `y beta`- Particles be given out during the change `._(92)U^(238) rarr ._(82)Pb^(206) + x_(2)He^(4) + y ._(-1)e^(0)` Equating mass number on both sides
`238 = 206 + 4x y xx 0`
or `x = 8`
Equating atomic number on both sides
`92 = 82 + 2x + y (-1)`
`= 82 + 2 xx 8 + y (-1)`
or `y = 6`
`:.` Number of `alpha`-particles = 8, Number of `beta- particles = 6
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