In the radioacitve decay
`._(Z)X^(A) rarr ._(z + 1)Y^(A) rarr ._(z - 1)^(A - 4) rarr ._(z - 1)Z^(*A - 4)`
The sequence of emission is
a. `alpha, beta, gamma` b. `gamma, alpha, beta` c. `beta, alpha, gamma` c. `beta, gamma, alpha`

Explanation

To solve the problem, we need to analyze the given radioactive decay sequence step by step. The decay sequence is:

1. **Step 1: X → Y**
- Here, the atomic number increases from Z to Z + 1, while the mass number remains the same (A).
- This type of decay occurs during **beta decay**, where a beta particle (electron) is emitted, resulting in the transformation of a neutron into a proton.

2. **Step 2: Y → Z**
- In this step, the atomic number decreases from Z + 1 to Z - 1, and the mass number decreases from A to A - 4.
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