What may be the new neutron and proton ratio after a nuclide `._(92)U^(238)` loses an `alpha`-particles?

Explanation

To find the new neutron and proton ratio after the nuclide \( _{92}^{238}U \) loses an alpha particle, we can follow these steps:

### Step 1: Identify the nuclide and the alpha particle
The nuclide in question is Uranium-238, represented as \( _{92}^{238}U \). An alpha particle is a helium nucleus, which has a mass number of 4 and an atomic number of 2.

### Step 2: Determine the new nuclide after alpha emission
When Uranium-238 emits an alpha particle, it loses 4 units of mass (from the mass number) and 2 units of charge (from the atomic number). Therefore, the new nuclide can be calculated as follows:
- New mass number = \( 238 - 4 = 234 \)
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