Home
Class 12
CHEMISTRY
IN radioactive series, an inner transiti...

IN radioactive series, an inner transition element `._(92)U^(238)` loses one `alpha`-particles and one `beta`-particle to produce a very unstable daughter nuclei `._(91)Pa^(234)` with half life 1.14 min. Find out the displacement in group due to these emissions.

Text Solution

AI Generated Solution

To solve the problem, we will analyze the decay process of uranium-238 (U-238) through alpha and beta emissions and determine the displacement in the periodic table. ### Step-by-Step Solution: 1. **Identify the Initial Element:** The initial element is Uranium-238, which has: - Atomic Number (Z) = 92 - Mass Number (A) = 238 ...
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Example|18 Videos

  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex6.1 Objective|15 Videos

  • NCERT BASED EXERCISE

    CENGAGE CHEMISTRY ENGLISH|Exercise Nuclear Chemistry (NCERT Exercise)|29 Videos

  • ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Analytical And Descriptive|24 Videos

Similar Questions

Explore conceptually related problems

._(92)U^(238) is a natural alpha -emitter. After alpha -emission the residual nucleus U_(X1) in turn emits a beta -particle to produce another nucleus U_(X2) . Find out the atomic number and mass number of U_(X1) and U_(X2) .

._(92)U^(238) is a natural alpha -emitter. After alpha -emission the residual nucleus U_(X1) in turn emits a beta -particle to produce another nucleus U_(X2) . Find out the atomic number and mass number of U_(X1) and U_(X2) .

In the disintegration of a radioactive element, alpha - and beta -particles are evolved from the nucleus. ._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0) + Antineutrino + Energy 4 ._(1)H^(1) rarr ._(2)He^(4) + 2 ._(+1)e^(0) + Energy Then, emission of these particles changes the nuclear configuration and results into a daughter nuclide. Emission of an alpha -particles results into a daughter element having atomic number lowered by 2 and mass number by 4, on the other hand, emission of a beta -particle yields an element having atomic number raised by 1. A radioactive element belongs to III B group, it emits ona alpha - and beta -particle to form a daughter nuclide. The position of daughter nuclide will be in

Nuceli A and B convert into a stable nucleus C . Nucleus A is converted into C by emitting 2 alpha particels and 3 beta -particles. Nucleus B is converted into C by emitting one alpha -particle and 5 beta -particles. At time t=0 , nuclei of A are 4N_(0) and nuceli of B are N_(0) . Initially, number of nuclei of C are zero. Half-life of A (into conservation of C ) is 1 min and that of B is 2 min . Find the time (in minutes) at which rate of disintegration of A and B are equal.

Uranium "_(92)^(238)U is an unstable nucleaus. It decays to Thorium "_(90)^(234)Th , which is again an unstable nuclei which further decays to "_(91)^(234)Pa . Such decay is called successive dlsntegration. Let "_(92)^(238)U is called as A of decay constant lambda_(1) and "_(90)^(234)Th is called as B of decay constant lambda_(2) and stable nuclei "_(91)^(234)Pa is named as C . Here A is called parent nucleus and B is called daughter nucleus of A . Any two adjacent nuclei may be consider parem daughter nuclei. Suppose N_(1) , N_(2) and N_(3) are number of nuclei A , B and C respectively at time t which undergoes decay. Then we can write Aoverset(lambda_(2))(to)Boverset(lambda_(2))(to)C Rate of disintegration of A=(dN_(1))/(dt)= -lambda_(1)N_(1) Rate of disintegration of B= -lambda_(2)N_(2) and net rate of formation of B=(dN_(2))/(dt)=lambda_(1)N_(1)-lambda_(2)N_(2) Rate of formation of nuclei C is equal to (dN_(3))/(dt)=lambda_(2)N_(2) If at t=0 , there are N_(0) number of nuclei of A , where as nuclei B and C are absent in the sample answer the following questions The graph between N_(1) , N_(2) & N_(3) with time can be best represented by

""_(92)^(238) U(IIIB) changes to ""_(9)^(234) Th by emission of alpha - particle . Daughter element will be in -

Uranium ._(92)^(238)U is an ustable nucleus. It decays to Thorium ._(92)^(238)Th , which is again an unstable nucleus which further decays to ._(91)^(234)Pa . Let ._(92)^(238)U be called A of decay constant lambda_(1) and ._(90)^(234)Th is called as B of decay constant lambda_(2) and stable nuclei ._(91)^(234)Pa be called as C . Here A is called parent nucleus and B is called daughter nucleus of A . Any two adjacent nuclei may be consider parent or daughter nuclei A, B and C respectively at time 't' . Then we can write Aoverset(lambda_(1))rarrBoverset(lambda_(2))rarrC Rate of disintergration of A=(dN_(1))/(dt)=-lambda_(1)N_(1) Rate of disintergration of B=(dN_(2))/(dt)=lambda_(1)N_(1)-lambda_(2)N_(2) Rate of formation of nuclei C is equal to (dN_(3))/(dt)=-lambda_(2)N_(2) If at t=0 , there are N_(0) number of nuclei of A where as nuclei B and C are absent in the sample Answer the following questions ltbgt Numeber of the nuclei of nuclei C at time t is

Uranium ._(92)^(238)U is an ustable nucleus. It decays to Thorium ._(92)^(238)Th , which is again an unstable nucleus which further decays to ._(91)^(234)Pa . Let ._(92)^(238)U be called A of decay constant lambda_(1) and ._(90)^(234)Th is called as B of decay constant lambda_(2) and stable nuclei ._(91)^(234)Pa be called as C . Here A is called parent nucleus and B is called daughter nucleus of A . Any two adjacent nuclei may be consider parent or daughter nuclei A, B and C respectively at time 't' . Then we can write Aoverset(lambda_(1))rarrBoverset(lambda_(2))rarrC Rate of disintergration of A=(dN_(1))/(dt)=lambda_(1)N_(1) Rate of disintergration of B=(dN_(2))/(dt)=lambda_(1)N_(1)-lambda_(2)N_(2) Rate of formation of nuclei C is equal to (dN_(3))/(dt)=lambda_(2)N_(2) If at t=0 , there are N_(0) number of nuclei of A where as nuclei B and C are absent in the sample Answer the following questions Number of nuclei of B at any time t is

(a) Calculate the activity of one mg sample ._(28^(Sr^(90))) whose half life period is 28 years. (b) An experiment is performed to determine the half-life of a radioactive substance which emits one beta particle for each decay process. Observation shown that an average of 8.4 beta- particles are emitted each second by 2.5 mg of the substance. the atomic weight of the substance is 230 . calculate the half0life of the substance. (c) Determine the quantity of ._(84^(Po^(210))) necessary to provide a source of alpha particle of 5mCi strength ( T_(1//2) for Po = 138 day).

Various rules of thumb have seen proposed by the scientific community to expalin the mode of radioactive decay by various radioisotopes. One of the major rules is called the n//p ratio. If all the known isotopes of the elemnts are plotted on a graph of number of neutrons (n) versus number of protons (p), it is observed that all isotopes lying outside of a ''stable'' n//p ratio region are radioactive as shown fig.5.28. The graph exhibits straight line behaviour with unit slope up to p=25 . Above p=25 , tgose isotopes with n//p ratios lying above the stable region usually undergo beta decay. Very heavy isotopes (pgt83) are unstable because of their relativley large nuclei and they undergo alpha decay. Gamma ray emission does not involve the release of a particle. It represnts a change in an atom from a higher energy level to a lower energy level. Which of the following represents the relative penetrating power of the three types of radioactive emission in decreasing order?