A follow parallel path of first-order reactions giving `B` and `C` as
If the initial concentration of `A` is `0.25 M`, calculate the concentration of `C` after 5 hr of reaction.

Explanation

`lambda_(A) = lambda_(1) + lambda_(2) = .15 xx 10^(-5) + 5 xx 10^(-6) = 20 xx 10^(-6) s^(-1)`
Also, `2.303 log ([A]_(0))/([A]_(t)) = lambdas xx t`
`:. 2.303 log (0.25)/([A]_(t)) = 20 xx 10^(-6) xx 5 xx 60 xx 60`
`:. [A]_(t) = 0.1744 M`
`:. [A]_("decompound") = [A]_(0) - [A]_(t) = 0/25 - 0.1744`
`= 0.-756 = M`
Fraction of `C` formed `= [(lambda_(2))/(lambda_(1) + lambda_(2))] xx [A]_("decomposed") xx (2)/(5)`
`= 0.0756 xx (5 xx 10^(-6))/(20 xx 10^(-6)) xx (2)/(5)`
`= 7.56 xx 10^(-3) M`