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One mole of X present in a closed vessel...

One mole of `X` present in a closed vessel undergoes decays as:
`._(Z)X^(A) rarr ._(Z - 2)Y^(A - 4) + (._(2)He^(4))`
What will be the volume of helium gas collected as `SATP` and `STP` (1 bar pressures, `273 K` temperature) after 20 days `(t_(1//2) "of" A = 10` days)?

Text Solution

AI Generated Solution

To solve the problem step by step, we will follow the decay process of the substance `X` and calculate the volume of helium gas produced after 20 days. ### Step 1: Understand the decay process The reaction given is: \[ _{Z}X^{A} \rightarrow _{Z-2}Y^{A-4} + _{2}He^{4} \] From this reaction, we see that 1 mole of `X` produces 1 mole of helium gas (`He`). ...
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