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75% of a first order reaction was comple...

75% of a first order reaction was completed in 32 minutes. When was 50% of the reaction completed ?

A

a. 24 min

B

b. 16 min

C

c. 8 min

D

d. 4 min

Text Solution

Verified by Experts

The correct Answer is:
b. 16 min
Use direct formula `(t_(x%))/(t_(y%)) = ("log" (a)/(a - x))/("log" (a)/(a - y))`
`:. (t_(50%))/(t_(75%)) = ("log" (100)/(100 - 50))/("log" (100)/(100 - 75)) implies t_(50%) = (t_(75%))/(2)`
`:.t_(32)/(2) = 16 "min"`
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