Home
Class 12
CHEMISTRY
The beta activity of 1 g of carbon made ...

The beta activity of `1 g` of carbon made from green wood is 15.3 counts per minute. If the activity of `1 g` of carbon derived from the wood of an Egyptian mummy case is 9.4 counts per minute under the same conditions, how old is the wood of the mummy case?

Text Solution

AI Generated Solution

To determine the age of the wood from the mummy case based on its beta activity, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Data**: - The beta activity of `1 g` of carbon from green wood (fresh wood) is `15.3 counts per minute`. - The beta activity of `1 g` of carbon from the wood of the Egyptian mummy case is `9.4 counts per minute`. ...
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Example|18 Videos

  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex6.1 Objective|15 Videos

  • NCERT BASED EXERCISE

    CENGAGE CHEMISTRY ENGLISH|Exercise Nuclear Chemistry (NCERT Exercise)|29 Videos

  • ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Analytical And Descriptive|24 Videos

Similar Questions

Explore conceptually related problems

The beta- activity of a sample of CO_(2) prepared form a contemporary wood gave a count rate of 25.5 counts per minute (cp m) . The same of CO_(2) form an ancient wooden statue gave a count rate of 20.5 cp m , in the same counter condition. Calculate its age to the nearest 50 year taking t_(1//2) for .^(14)C as 5770 year. What would be the expected count rate of an identical mass of CO_(2) form a sample which is 4000 year old?

A piece of wood form the ruins of an ancient building was found to have a C^(14) activity of 12 disintegrations per minute per gram of its carbon content. The C^(14) activity of the living wood is 16 disintegrations/minute/gram. How long ago did the trees, from which the wooden sample came, die? Given half-life of C^(14) is 5760 years.

A solution containing active cobalt 60/27 Co having activity of 0.8 muCi and decay constant lambda is injected in an animal's body. If 1cm^(3) of blood is drawn from the animal's body after 10hrs of injection , the activity found was 300 decays per minute. What is the volume of blood that is flowing in the body ? ( 1 Ci = 3.7 xx 10^(10) decays per second and at t = 10 hrs e^(-lambdat) = 0.84 )

As mosquito is sitting on an L.P. record disc rotating on a trun tabel at 33 1/3 revolutions per minute. The distance of the mosquito from the centre of the turn table is 10 cm. Show that the friction coefficient between the record and the mosquito is greater than pi^2/81 . Take g=10m/s^2

A rocket, with an initial mass of 1000kg , is launched vertically upwards from rest under gravity. The rocket burns fuel at the rate of 10kg per second. The burnt matter is ejected vertically downwards with a speed of 2000ms^-1 relative to the rocket. If burning ceases after one minute, find the maximum velocity of the rocket. (Take g as constant at 10ms^-2 )

A military band was marching on a street in the same direction as the normal traffic flow. A motorist was approching the band from behind in his car just at the moment when they were playing the musical note A (frequency 440 Hz ) in unison. The same band' performance was also simultaneously being broad live on the ratio from a stationary microphone which was situated on the sidewalk just ahead of the band. The motorist noticed that the combination of the direct sound coming from the band ahead of the band brodcast produced discernible beats. Timing the beats, he counted 4 beats in 3 seconds. He noted from the speedmeter that his car was travelling at 18 kilometers per hour. Calculate the speed in meters per seconds at which the band was marching assuming that the speed of sound on that day was 330 ms^(-1) . (It was a very cold day)

An amusement park ride consist of a large verticle cylinder that spins about its axis first fast enough that any person inside is held up againest the wall when the is mu_(s) and the radius of the cylider is R a. Shown that maximum period of revolation neccessary to keep the person from falling is T = (4 pi^(2) mu_(s) R //g)^(1//2) b. Obtain a numerical value for T taking R = 4.00m and mu_(s) = 0.400 . How many revolations per minute does the cylinder make? c. If the rate of revolation of the cylinder is make to be some what larger what happens to the magnitude of each one of the forces acting on the person ? What happens to the motion of the person ? d. If instead the cylinder rate revolution is made to be somewhat smaller what happens to the magnitude and what happens to the motion of the person ?