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U-235 is decayed by bombardment by neutr...

`U-235` is decayed by bombardment by neutron as according to the equation:
`._(92)U^(235) + ._(0)n^(1) rarr ._(42)Mo^(98) + ._(54)Xe^(136) + x ._(-1)e^(0) + y ._(0)n^(1)`
Calculate the value of `x` and `y` and the energy released per uranium atom fragmented (neglect the mass of electron). Given masses (amu) `U-235 = 235.044`,
`Xe = 135.907, Mo = 97.90, e = 5.5 xx 10^(-4), n = 1.0086`.

Text Solution

AI Generated Solution

To solve the given nuclear reaction and calculate the values of \( x \) and \( y \), as well as the energy released per uranium atom fragmented, we will follow these steps: ### Step 1: Write down the nuclear reaction equation The reaction is given as: \[ _{92}^{235}U + _{0}^{1}n \rightarrow _{42}^{98}Mo + _{54}^{136}Xe + x \, _{-1}^{0}e + y \, _{0}^{1}n \] ...
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