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The isotopic masses of .(1)H^(2) and .(2...

The isotopic masses of `._(1)H^(2)` and `._(2)He^(4)` are 2.0141 and 4.0026 amu, respectively. Calculate the quantity of energy liberated when two moles of `._(1)H^(2)` undergo fission to form 1 mol of `._(2)He^(4)`. The velocity of light in vacuum is `3.0 xx 10^(8) m s^(-1)`.

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To solve the problem, we need to calculate the energy liberated when two moles of deuterium (\( _{1}^{2}H \)) undergo fission to form one mole of helium (\( _{2}^{4}He \)). We will follow these steps: ### Step 1: Identify the mass defect The mass defect (\( \Delta m \)) can be calculated using the formula: \[ \Delta m = 2 \times \text{mass of } _{1}^{2}H - \text{mass of } _{2}^{4}He \] Given: ...
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