The actual atomic mass of `._(20)Ca^(40)` is 39.96259 amu. Find the binding energy for this nuclide, using 1.008665 amu for the mass of a neutron and 1.007825 amu for the mass of atomic hydrogen. Also calculate the binding energy per nucleon.

Explanation

To find the binding energy for the nuclide \( _{20}^{40}\text{Ca} \) and the binding energy per nucleon, we will follow these steps:

### Step 1: Determine the Theoretical Mass
The theoretical mass of the calcium nuclide can be calculated using the number of protons and neutrons it contains. Calcium-40 has:
- 20 protons
- 20 neutrons

The mass of a proton is given as 1.008665 amu, and the mass of a neutron is given as 1.008665 amu.
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