It is found that `3.125 xx 10^(-8) g` atoms of `Rn` exist in equilibrium with `1 g` of radium at `0^(@)C` and 1 atm pressure. The disintegration Constant of `Ra` is `1.48 xx 10^(11) s^(-1)`. Calculate the disintegration cosntant of `Rn`.

Explanation

To solve the problem, we need to calculate the disintegration constant of radon (Rn) given the disintegration constant of radium (Ra) and the amount of radon in equilibrium with radium.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Mass of radon (Rn) = \(3.125 \times 10^{-8} \, \text{g}\)
- Mass of radium (Ra) = \(1 \, \text{g}\)
- Disintegration constant of radium (\(\lambda_{Ra}\)) = \(1.48 \times 10^{-11} \, \text{s}^{-1}\)
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