Quantity of radiactive material which undergoes `10^(6)` disintegrations per second is called

Options

A. Becquerel
B. Rutherford
C. Curie
D. Faraday

Answer

To solve the question regarding the quantity of radioactive material which undergoes \(10^6\) disintegrations per second, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Radioactive Decay**:
- Radioactive decay refers to the process by which an unstable atomic nucleus loses energy by emitting radiation. The rate of decay is measured in terms of disintegrations per second.

2. **Defining Activity**:
- The activity of a radioactive substance is defined as the number of disintegrations that occur in a unit time. It is usually expressed in disintegrations per second (DPS).

3. **Identifying Units of Activity**:
- The unit of activity can be expressed in different terms:
- 1 disintegration per second (DPS) is equivalent to 1 Becquerel (Bq).
- 1 Rutherford is defined as \(10^6\) disintegrations per second.
- 1 Curie (Ci) is defined as \(3.7 \times 10^{10}\) disintegrations per second.

4. **Analyzing the Given Quantity**:
- The question states that the quantity of radioactive material undergoes \(10^6\) disintegrations per second.

5. **Matching with Known Units**:
- Since \(10^6\) disintegrations per second corresponds to 1 Rutherford, we can conclude that the quantity of radioactive material in question is measured in Rutherford.

6. **Final Answer**:
- Therefore, the quantity of radioactive material which undergoes \(10^6\) disintegrations per second is called **Rutherford**.

### Conclusion:
The answer to the question is **Rutherford**.

---