Home
Class 12
CHEMISTRY
There are four radioactive decay series ...

There are four radioactive decay series called thorium `(4n)`, uranium `(4n + 2)` actinium `(4n + 3)` and neptunium `(4n + 1)` series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth.
`._(86)Rn^(219)` is a member of actinium series. Another member of same series is

A

`._(92)U^(235)`

B

`._(89)Ac^(222)`

C

`._(90)Th^(212)`

D

`._(84)Po^(212)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify another member of the actinium decay series, given that radon-219 (Rn-219) is a member of this series. The actinium series is characterized by the formula \(4n + 3\), where \(n\) is a non-negative integer. This means that when the mass number of an element in this series is divided by 4, the remainder should be 3. ### Step-by-Step Solution: 1. **Identify the Mass Number of Rn-219**: - The mass number of radon is 219. 2. **Check the Remainder of Rn-219**: - Divide 219 by 4: \[ 219 \div 4 = 54 \quad \text{(with a remainder of 3)} \] - Since the remainder is 3, Rn-219 indeed belongs to the actinium series. 3. **Identify Other Members of the Actinium Series**: - We need to find another element whose mass number, when divided by 4, also gives a remainder of 3. 4. **Check the Mass Number of Uranium-235**: - The mass number of uranium is 235. - Divide 235 by 4: \[ 235 \div 4 = 58 \quad \text{(with a remainder of 3)} \] - Since the remainder is also 3, uranium-235 (U-235) is another member of the actinium series. 5. **Check Other Options**: - We can check other elements like actinium-227 (Ac-227) and polonium-212 (Po-212) to confirm they do not belong to the actinium series: - For Ac-227: \[ 227 \div 4 = 56 \quad \text{(with a remainder of 3)} \] - Ac-227 also belongs to the actinium series. - For Po-212: \[ 212 \div 4 = 53 \quad \text{(with a remainder of 0)} \] - Po-212 does not belong to the actinium series. 6. **Conclusion**: - Therefore, both uranium-235 and actinium-227 are members of the actinium series along with radon-219. ### Final Answer: Another member of the actinium series is **Uranium-235 (U-235)**.
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Multiple Correct|26 Videos
  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Single Correct|80 Videos
  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex6.5 Objective|10 Videos
  • NCERT BASED EXERCISE

    CENGAGE CHEMISTRY ENGLISH|Exercise Nuclear Chemistry (NCERT Exercise)|29 Videos
  • ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Analytical And Descriptive|24 Videos

Similar Questions

Explore conceptually related problems

There are four radioactive decay series called thorium (4n) , uranium (4n + 2) actinium (4n + 3) and neptunium (4n + 1) series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth. Actinium series begins with an isotope of

There are four radioactive decay series called thorium (4n) , uranium (4n + 2) actinium (4n + 3) and neptunium (4n + 1) series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth. The end products of uranium and actinium series are, respectively

There are four radioactive decay series called thorium (4n) , uranium (4n + 2) actinium (4n + 3) and neptunium (4n + 1) series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth. The starting isotope and the end product: isotope of actinium series are

There are four radioactive decay series called thorium (4n) , uranium (4n + 2) actinium (4n + 3) and neptunium (4n + 1) series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth. The end product formed in the disintegration of ._(88)Ra^(222) is

._(89)Ac^(227) is a member of actinium series. Another member of the same series of

The end product of 4n series is

What is the end product of natural radioactive series?

The decay constant of the end product of a radioactive series is

The end product of (4n + 2) disintegration series is

The end product of (4n+3) series if ?

CENGAGE CHEMISTRY ENGLISH-NUCLEAR CHEMISTRY-Exercises Link Comprehension
  1. There are four radioactive decay series called thorium (4n), uranium (...

    Text Solution

    |

  2. There are four radioactive decay series called thorium (4n), uranium (...

    Text Solution

    |

  3. There are four radioactive decay series called thorium (4n), uranium (...

    Text Solution

    |

  4. There are four radioactive decay series called thorium (4n), uranium (...

    Text Solution

    |

  5. There are four radioactive decay series called thorium (4n), uranium (...

    Text Solution

    |

  6. The activity of a nucleus is inversely proportional to its half of ave...

    Text Solution

    |

  7. The activity of a nucleus is inversely proportional to its half of ave...

    Text Solution

    |

  8. The activity of a nucleus is inversely proportional to its half of ave...

    Text Solution

    |

  9. Unstable nuclei attain stability through disintegration. The nuclear s...

    Text Solution

    |

  10. Unstable nuclei attain stability through disintegration. The nuclear s...

    Text Solution

    |

  11. Unstable nuclei attain stability through disintegration. The nuclear s...

    Text Solution

    |

  12. Unstable nuclei attain stability through disintegration. The nuclear s...

    Text Solution

    |

  13. Unstable nuclei attain stability through disintegration. The nuclear s...

    Text Solution

    |

  14. In the disintegration of a radioactive element, alpha- and beta-partic...

    Text Solution

    |

  15. In the disintegration of a radioactive element, alpha- and beta-partic...

    Text Solution

    |

  16. In the disintegration of a radioactive element, alpha- and beta-partic...

    Text Solution

    |

  17. In the disintegration of a radioactive element, alpha- and beta-partic...

    Text Solution

    |

  18. In the decay series .(92)U^(238) to .(82)Pb^(206), how many alpha-pari...

    Text Solution

    |

  19. Uranium .(92)U^(238) decayed to .(82)Pb^(206). They decay process is ....

    Text Solution

    |

  20. Uranium .(92)U^(238) decayed to .(82)Pb^(206). They decay process is ....

    Text Solution

    |