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There are four radioactive decay series called thorium `(4n)`, uranium `(4n + 2)` actinium `(4n + 3)` and neptunium `(4n + 1)` series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth.
The starting isotope and the end product: isotope of actinium series are

A

`._(88)Ac^(227)` and `._(82)Pb^(208)`

B

`._(92)U^(235)` and `._(82)Pb^(207)`

C

`._(92)U^(238)` and `._(82)Pb^(207)`

D

`._(92)U^(235)` and `._(82)Pb^(208)`

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To solve the question regarding the starting isotope and the end product of the actinium series, we will follow these steps: ### Step 1: Understand the Actinium Series The actinium series is represented by the formula \(4n + 3\), where \(n\) is a non-negative integer. This means that the mass number of isotopes in this series, when divided by 4, will leave a remainder of 3. ### Step 2: Identify the End Product According to the information provided, the natural decay series, including the actinium series, terminates at lead (Pb). Therefore, the end product of the actinium series is lead. ### Step 3: Determine the Isotope of Actinium We need to find a starting isotope that fits the \(4n + 3\) condition. We can check the mass numbers of known isotopes to find one that gives a remainder of 3 when divided by 4. ### Step 4: Check Uranium-235 Let's check uranium-235 (U-235): - Mass number = 235 - When we divide 235 by 4, we get: \[ 235 \div 4 = 58 \quad \text{(remainder 3)} \] Since the remainder is 3, U-235 is indeed part of the actinium series. ### Step 5: Identify the End Product Isotope The end product of the actinium series is lead. The stable isotope of lead that we consider is lead-207 (Pb-207). ### Conclusion Thus, the starting isotope of the actinium series is uranium-235 (U-235), and the end product is lead-207 (Pb-207). ### Final Answer - Starting Isotope: Uranium-235 (U-235) - End Product: Lead-207 (Pb-207) ---
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There are four radioactive decay series called thorium (4n) , uranium (4n + 2) actinium (4n + 3) and neptunium (4n + 1) series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth. Actinium series begins with an isotope of

There are four radioactive decay series called thorium (4n) , uranium (4n + 2) actinium (4n + 3) and neptunium (4n + 1) series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth. The end product formed in the disintegration of ._(88)Ra^(222) is

There are four radioactive decay series called thorium (4n) , uranium (4n + 2) actinium (4n + 3) and neptunium (4n + 1) series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth. The end products of uranium and actinium series are, respectively

There are four radioactive decay series called thorium (4n) , uranium (4n + 2) actinium (4n + 3) and neptunium (4n + 1) series. Neptunium series is artificial while other three series are natural. The end productsd of each radioacitve decay series have stable nuclei. All natural decay series terminate at lead but neptunium or artificial series terminate at bismuth. ._(86)Rn^(219) is a member of actinium series. Another member of same series is

The end product of 4n series is

What is the end product of natural radioactive series?

The decay constant of the end product of a radioactive series is

The end product of (4n + 2) disintegration series is

The end product of (4n+3) series if ?

Sum up to n terms the series

CENGAGE CHEMISTRY ENGLISH-NUCLEAR CHEMISTRY-Exercises Link Comprehension
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  8. Unstable nuclei attain stability through disintegration. The nuclear s...

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  9. Unstable nuclei attain stability through disintegration. The nuclear s...

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  10. Unstable nuclei attain stability through disintegration. The nuclear s...

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  11. Unstable nuclei attain stability through disintegration. The nuclear s...

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  12. In the disintegration of a radioactive element, alpha- and beta-partic...

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  13. In the disintegration of a radioactive element, alpha- and beta-partic...

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  14. In the disintegration of a radioactive element, alpha- and beta-partic...

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  15. In the disintegration of a radioactive element, alpha- and beta-partic...

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  16. In the decay series .(92)U^(238) to .(82)Pb^(206), how many alpha-pari...

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  17. Uranium .(92)U^(238) decayed to .(82)Pb^(206). They decay process is ....

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  18. Uranium .(92)U^(238) decayed to .(82)Pb^(206). They decay process is ....

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  19. Uranium .(92)U^(238) decayed to .(82)Pb^(206). They decay process is ....

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  20. The source of energy of stars is nuclear fusion. Fusion reaction occur...

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