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From the reaction given below, deduce th...

From the reaction given below, deduce the group of polonium in the periodic table (Pb belongs to group 14)
`._(84)Po^(210) rarr ._(82)Pb^(206) + ._(2)He^(4)`

A

2

B

14

C

6

D

16

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The correct Answer is:
To deduce the group of polonium (Po) in the periodic table based on the given nuclear reaction, we can follow these steps: ### Step 1: Analyze the given nuclear reaction The reaction provided is: \[ _{84}^{210}\text{Po} \rightarrow _{82}^{206}\text{Pb} + _{2}^{4}\text{He} \] Here, polonium (Po) has an atomic number of 84 and a mass number of 210. It decays into lead (Pb) with an atomic number of 82 and a mass number of 206, releasing an alpha particle (helium nucleus) with an atomic number of 2 and a mass number of 4. ### Step 2: Understand the relationship between atomic numbers and groups In the periodic table, the group number of an element is related to its atomic number. The group number can often be determined by the atomic number of the element. ### Step 3: Determine the atomic number of polonium From the reaction, we see that polonium has an atomic number of 84. ### Step 4: Determine the atomic number of lead Lead has an atomic number of 82, as given in the reaction. ### Step 5: Relate the atomic numbers to the group numbers Since lead (Pb) belongs to group 14, we can set up the following relationship: - Let the group number of polonium be \( X \). - The group number of lead is \( X - 2 \) (since the decay involves the emission of an alpha particle, which decreases the atomic number by 2). ### Step 6: Set up the equation From the information given: \[ X - 2 = 14 \] ### Step 7: Solve for \( X \) Adding 2 to both sides gives: \[ X = 14 + 2 \] \[ X = 16 \] ### Conclusion Thus, polonium (Po) belongs to group 16 in the periodic table.

To deduce the group of polonium (Po) in the periodic table based on the given nuclear reaction, we can follow these steps: ### Step 1: Analyze the given nuclear reaction The reaction provided is: \[ _{84}^{210}\text{Po} \rightarrow _{82}^{206}\text{Pb} + _{2}^{4}\text{He} \] Here, polonium (Po) has an atomic number of 84 and a mass number of 210. It decays into lead (Pb) with an atomic number of 82 and a mass number of 206, releasing an alpha particle (helium nucleus) with an atomic number of 2 and a mass number of 4. ### Step 2: Understand the relationship between atomic numbers and groups ...
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