When `n//p` ratio of an isotope is greater than the stable isotope of that element, it emits

Options

A. `beta`-particles
B. `alpha`-particles
C. Neutron
D. Positron

Explanation

To solve the question regarding the emission from an isotope when the neutron-to-proton (n/p) ratio is greater than that of the stable isotope of that element, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the n/p Ratio**:
- The n/p ratio (neutron-to-proton ratio) is crucial in determining the stability of a nucleus. Stable isotopes have a specific n/p ratio that allows them to remain stable.

2. **Identifying the Condition**:
- The question states that the n/p ratio of a given isotope is greater than that of the stable isotope. This indicates that there are more neutrons compared to protons than what is considered stable.

3. **Determining the Type of Decay**:
- When the n/p ratio is higher than the stable isotope, the nucleus is unstable. To achieve stability, the nucleus must adjust its n/p ratio.
- The most common way for a nucleus with a high n/p ratio to stabilize is through beta decay.

4. **Understanding Beta Decay**:
- In beta decay, a neutron is converted into a proton, and a beta particle (which is an electron) is emitted. This process increases the atomic number of the element by one while keeping the mass number the same.
- As a result, the n/p ratio decreases, moving it closer to the stable ratio.

5. **Conclusion**:
- Therefore, when the n/p ratio of an isotope is greater than that of the stable isotope, the isotope will emit beta particles to achieve stability.

### Final Answer:
The isotope emits beta particles.

---