The radioactive decay follows zero`-` order kinetics.

Answer

To solve the question regarding whether the radioactive decay follows zero-order kinetics, we can break down the reasoning step by step.

### Step-by-Step Solution:

1. **Understanding Radioactive Decay**:
- Radioactive decay is a process where an unstable nucleus transforms into a more stable nucleus by emitting radiation (alpha, beta, or gamma particles).

2. **Identifying the Rate of Decay**:
- In radioactive decay, the rate of disintegration (decay) is dependent on the number of undecayed (unstable) nuclei present.

3. **Formulating the Rate Equation**:
- The rate of decay can be expressed mathematically as:
\[ -\frac{dN}{dt} \propto N \]
where \( N \) is the number of undecayed atoms.

4. **Understanding the Proportionality**:
- This proportionality indicates that the rate of decay is directly proportional to the number of undecayed atoms.

5. **Converting Proportionality to an Equation**:
- By removing the proportionality, we can write the rate equation as:
\[ -\frac{dN}{dt} = kN \]
where \( k \) is the rate constant.

6. **Determining the Order of the Reaction**:
- The equation \( -\frac{dN}{dt} = kN \) indicates that the rate of decay is first-order because the rate is proportional to the concentration of the reactant raised to the power of 1.

7. **Conclusion**:
- Since the rate of radioactive decay is directly proportional to the number of undecayed atoms and follows first-order kinetics, the statement that radioactive decay follows zero-order kinetics is **false**.

### Final Answer:
The statement that the radioactive decay follows zero-order kinetics is **false**; it actually follows first-order kinetics.

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