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In Dumas’ method for estimation of nitro...

In Dumas’ method for estimation of nitrogen, 0.3g of an organic compound gave 50mL of nitrogen collected at 300K temperature and 715mm pressure. Calculate the percentage composition of nitrogen in the compound. (Aqueous tension at 300K=15 mm)

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Here mass of the substance taken `=0.30gm`
Atmospheric pressure `=715 mm` Hg
Vapour pressure of water at `300`
`K=15mm`
Volume of notrogen collected `=50ml`
Room temperature `=300K`
Actual pressure of the gas (dry gas) `=715-15=700mmHg`
To convert the volume at experimental conditions to volume at STP.
`{:("experiment at condition,At STP"),(P_1=700mm,P_2=760mm),(V_1=50ml,V_2=?),(T_1=300K,T_2=273K):}`
Substituting these values in the gas equation
`=(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`, we get
`(700mmxx50ml)/(300K)=(760mmxxV_2ml)/(273K)`
or `V_2=(273xx700xx50)/(300xx760)=41.9ml`
Step 2: Percentage of nitrogen
`=(28)/(22400)xx("Vol. of "N_2" at STP")/("Mass of compound")xx100`
`=(28xx41.9xx100)/(22400xx0.3)`
`=17.46`
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