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0.246 gm of an organic compound containi...

0.246 gm of an organic compound containing `58.53%` carbon and `4.06%` hydrogen gave 22.4 ml of nitrogen at STP. What is the empirical formula of the compound?

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To find the empirical formula of the organic compound, we will follow these steps: ### Step 1: Calculate the percentage of nitrogen in the compound. Given that the compound produced 22.4 ml of nitrogen gas (N₂) at STP, we can calculate the percentage of nitrogen in the compound. 1. **Volume of nitrogen at STP**: 22.4 ml 2. **Molar volume of gas at STP**: 22.4 L = 22400 ml 3. **Moles of nitrogen**: ...
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