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50 " mL of " a mixture of NH3 and H2 was...

50 " mL of " a mixture of `NH_3` and `H_2` was completely decomposed into `N_2` and `H_2` by sparking. 40 " mL of " `O_2` was then added and the mixture was sparked again. After cooling the mixture was shaken with alkaline pyrogallol and a contraction of 6 mL was observed. Calculate the percentage of `NH_3` in the original mixture.

Text Solution

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`underset(x y (x)/(2) (3)/(2) x y ml)NH_3+H_2rarr(1)/(2)N_2+(3)/(2)H_2+H_2`
`x+y=50ml` ..(i)
`(3)/(2)H_2+(3)/(4)O_2rarr(3)/(2)H_2O` ….(ii)
`(3)/(2)xml(3)/(4)xml`
`underset(y ml (y)/(2) ml y ml)H_2+(1)/(2)O_2rarrH_2O` …(iii)
[After shaking with pyrogallol solution, unreacted
`O_2` was absorbed 6ml constaction was observed. (initial volume of `O_2=40ml`
Unreacted `O_2=6ml`, reacted `O_2=40-6=34ml`]
From (ii) and (iii), `O_2` used
`(3)/(4)x+(y)/(2)=34implies3x+2y=34xx4` ..(iv)
From the equation (i) and (iv) solving
`{:(3x+2y=136),(x+y=50):}]impliesy=14,x=36`
percentage of `NH_3=(36)/(50)xx100=72%`
Total volume of organic compound `+O_2=95ml`
Volume of compound `=20ml`
volume of `O_2` used `=95-20=75ml`
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