0.984 g of a chloroplatinate salt of a diacid base on ignition gave 0.39 g of platinum. Find the molecular mass of the base.

Explanation

`("Molecular mass of chloroplatinate taken")/("atomic mass of platinum left")`
`=(0.49)/(0.195)`
Let B be the equivalent mass of the base
`(2B+410)/(195)=(0.49)/(0.195)`
or `2B=[(0.49)/(0.195)xx195-410]=80`
Molecular mass of the base `=` equivalent mass `xx` acidity
`=40xx2=80`