50 " mL of " pure and dry `O_2` was subjected to silent electric discharge and on cooling to the original temperature, the volume of ozonised oxygen was found to be 47 mL The gas was brought into contact with turpentine oil, after absorption of `O_3`, the remaining gas occupied 41 mL volume. What is the molecular formula of ozone?

Explanation

Volume of `O_2=50ml`
Let the formula of ozone be `O_x`
Volume of `O_2` (not converted to `O_x)+`ozone produced `=47ml`
Volume of `O_2` left (not converted to `O_x)=41ml`
Since ozone is absorbed in turpentine oil,
Volume of `O_2` converted to `O_x=50-41`
`=9ml`
Volume of ozone produced `=47-41`
`=6ml`
`{:(O_2,rarr,O_x),(9ml,,6ml),(9 mol es,,6 mol es):}`
Appying `POAC` rule (principle of atom conservation) for the O atom, we get
Number of O atoms `xx` moles of `O_2=` Number of O atoms `xx` moles of `O_x`
`=2xx9=x xx6`
`impliesx=3`
Hence, the formula of ozone is `O_3`.