Twenty millilitres of a gaseous hydrocarbon required 400 ml of iar for complete cumbustion. The air contains `20%` by explosion and cooling was found to be 380 ml.
Q. Formula of the hydrocarbon is:

Options

A. `Me^3-``^2-=^1-H`
B. `H-2C=C=CH_2`
C.
D. all

Answer

D

Explanation

D.U. in `C_3H_4=((2n_C+2)-n_H)/(2)=2^@`
Here 2 D.U. means it can have either one `(C-=C)` bond or two `(C=C)` bonds or cyclic compound with one `(C=C)` bond. The structures can be:
(I) `Me-C-=CH`
(II) `H_2C-C=CH_2`
(III)