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The catalyst used in Kjeldahl's method f...

The catalyst used in Kjeldahl's method for the entimation of nitrogen is:

A

Copper

B

Magnesium

C

Mercury

D

Sodium

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To solve the question regarding the catalyst used in Kjeldahl's method for the estimation of nitrogen, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Kjeldahl's Method**: - Kjeldahl's method is a widely used technique for determining the nitrogen content in organic compounds. It involves the conversion of nitrogen in the sample to ammonium sulfate. 2. **Identifying the Catalysts**: - The question provides several options for potential catalysts: copper, magnesium, mercury, and sodium. 3. **Recalling the Role of Catalysts**: - In Kjeldahl's method, a catalyst is required to facilitate the reaction when the organic compound is heated with concentrated sulfuric acid. 4. **Reviewing Common Catalysts in Kjeldahl's Method**: - The most commonly used catalysts in this method are copper sulfate and mercury. These catalysts help in the digestion of the organic material. 5. **Selecting the Correct Answer**: - Among the options provided, mercury is identified as a common catalyst used in Kjeldahl's method. Therefore, the correct answer is mercury. ### Final Answer: The catalyst used in Kjeldahl's method for the estimation of nitrogen is **mercury**. ---
To solve the question regarding the catalyst used in Kjeldahl's method for the estimation of nitrogen, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Kjeldahl's Method**: - Kjeldahl's method is a widely used technique for determining the nitrogen content in organic compounds. It involves the conversion of nitrogen in the sample to ammonium sulfate. 2. **Identifying the Catalysts**: ...
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Estimation of nitrogen: There are two methods for the estimation of nitrogen (i) Dumas method and (ii) Kjedahl's method. i. Dumas method: A known mass of compound is heated with copper oxide (CuO) in an atomsphere of CO_(2) , which gives free nitrogen along with CO_(2) and H_(2)O C_(x)H_(y)N_(z) + (2x + y//2) CuO rarr xCO_(2) + y//2 (H_(2)O) + z//2 (N_(2)) + (2x + y//2) CU The gaseous mixture is passed over a heated copper gauze which converts traces of nitrogen oxides formed to N_(2) . The gaeous mixture is collected over an aqueous solution of KOH which absorbs CO_(2) , and nitrogen is callected in the upper part of the graduated tube. ii. Kjeldahl's method: A known mass of organic compound (0.5 gm) is mixed with K_(2)SO_(4) (10 gm) and CuSO_(4) . (1.0 gm) or a drop of mercury (Hg) and conc. H_(2)SO_(4) (25ml), and heated in Kjeldahl's flask. CuSO_(4) or Hg acts as a catalyst, while K_(2)SO_(4) raises the boiling point of H_(2)SO_(4) . The nitrogen in the organic compound is quantitatively converted to ammonium sulphate. The resulting mixture is then distilled with excess of NaOH solution and the NH_(3) evolved is passed into a known but excess volume of standard HCl or H_(2)SO_(4) . The acid left unused is estimated by titration with some standard alkali. The amount of acid used against NH_(3) can be thus be known and from this the percentage of nitrogen is calculated. (a) C + H + S underset(H_(2)SO_(4))overset("conc.")rarr CO_(2) + H_(2)O + SO_(2) (b) N underset(H_(2)SO_(4))overset("conc.")rarr (NH_(4))_(2)SO_(4) (c) (NH_(4))_(2) SO_(4) + 2NaOH rarr Na_(2)SO_(4) + 2NH_(3) + 2H_(2)O (d) 2NH_(3) + H_(2)SO_(4) rarr (NH_(4))_(2) SO_(4) (iii) This method is not applicable to compounds containing N in intro and azo groups, and N present in the ring (e.g., pyridine) as N of these compounds does not change to (NH_(4))_(2)SO_(4) (ammonium sulphate) under these reaction conditions 0.50 gm of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50ml of 0,5M H_(2)SO_(4) . The residual acid required 60 ml of M/2 NaOH solution. Find the percentage of nitrogen in the compound

Estimation of nitrogen: There are two methods for the estimation of nitrogen (i) Dumas method and (ii) Kjedahl's method. i. Dumas method: A known mass of compound is heated with copper oxide (CuO) in an atomsphere of CO_(2) , which gives free nitrogen along with CO_(2) and H_(2)O C_(x)H_(y)N_(z) + (2x + y//2) CuO rarr xCO_(2) + y//2 (H_(2)O) + z//2 (N_(2)) + (2x + y//2) CU The gaseous mixture is passed over a heated copper gauze which converts traces of nitrogen oxides formed to N_(2) . The gaeous mixture is collected over an aqueous solution of KOH which absorbs CO_(2) , and nitrogen is callected in the upper part of the graduated tube. ii. Kjeldahl's method: A known mass of organic compound (0.5 gm) is mixed with K_(2)SO_(4) (10 gm) and CuSO_(4) . (1.0 gm) or a drop of mercury (Hg) and conc. H_(2)SO_(4) (25ml), and heated in Kjeldahl's flask. CuSO_(4) or Hg acts as a catalyst, while K_(2)SO_(4) raises the boiling point of H_(2)SO_(4) . The nitrogen in the organic compound is quantitatively converted to ammonium sulphate. The resulting mixture is then distilled with excess of NaOH solution and the NH_(3) evolved is passed into a known but excess volume of standard HCl or H_(2)SO_(4) . The acid left unused is estimated by titration with some standard alkali. The amount of acid used against NH_(3) can be thus be known and from this the percentage of nitrogen is calculated. (a) C + H + S underset(H_(2)SO_(4))overset("conc.")rarr CO_(2) + H_(2)O + SO_(2) (b) N underset(H_(2)SO_(4))overset("conc.")rarr (NH_(4))_(2)SO_(4) (c) (NH_(4))_(2) SO_(4) + 2NaOH rarr Na_(2)SO_(4) + 2NH_(3) + 2H_(2)O (d) 2NH_(3) + H_(2)SO_(4) rarr (NH_(4))_(2) SO_(4) (iii) This method is not applicable to compounds containing N in intro and azo groups, and N present in the ring (e.g., pyridine) as N of these compounds does not change to (NH_(4))_(2)SO_(4) (ammonium sulphate) under these reaction conditions 0.4gm of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50ml of 0.5M H_(3)PO_(3) . The residual acid required 30 ml of 0.5M Ca(OH)_(2) . Find the percentage of N_(2) in the compound

Estimation of nitrogen: There are two methods for the estimation of nitrogen (i) Dumas method and (ii) Kjedahl's method. i. Dumas method: A known mass of compound is heated with copper oxide (CuO) in an atomsphere of CO_(2) , which gives free nitrogen along with CO_(2) and H_(2)O C_(x)H_(y)N_(z) + (2x + y//2) CuO rarr xCO_(2) + y//2 (H_(2)O) + z//2 (N_(2)) + (2x + y//2) CU The gaseous mixture is passed over a heated copper gauze which converts traces of nitrogen oxides formed to N_(2) . The gaeous mixture is collected over an aqueous solution of KOH which absorbs CO_(2) , and nitrogen is callected in the upper part of the graduated tube. ii. Kjeldahl's method: A known mass of organic compound (0.5 gm) is mixed with K_(2)SO_(4) (10 gm) and CuSO_(4) . (1.0 gm) or a drop of mercury (Hg) and conc. H_(2)SO_(4) (25ml), and heated in Kjeldahl's flask. CuSO_(4) or Hg acts as a catalyst, while K_(2)SO_(4) raises the boiling point of H_(2)SO_(4) . The nitrogen in the organic compound is quantitatively converted to ammonium sulphate. The resulting mixture is then distilled with excess of NaOH solution and the NH_(3) evolved is passed into a known but excess volume of standard HCl or H_(2)SO_(4) . The acid left unused is estimated by titration with some standard alkali. The amount of acid used against NH_(3) can be thus be known and from this the percentage of nitrogen is calculated. (a) C + H + S underset(H_(2)SO_(4))overset("conc.")rarr CO_(2) + H_(2)O + SO_(2) (b) N underset(H_(2)SO_(4))overset("conc.")rarr (NH_(4))_(2)SO_(4) (c) (NH_(4))_(2) SO_(4) + 2NaOH rarr Na_(2)SO_(4) + 2NH_(3) + 2H_(2)O (d) 2NH_(3) + H_(2)SO_(4) rarr (NH_(4))_(2) SO_(4) (iii) This method is not applicable to compounds containing N in intro and azo groups, and N present in the ring (e.g., pyridine) as N of these compounds does not change to (NH_(4))_(2)SO_(4) (ammonium sulphate) under these reaction conditions 0.002 gm of an organic compound was treated according to Kjeldahl's method. 0.2 xx 10^(-4) mol of H_(2)SO_(4) was required to neutralise NH_(3) . Calculate the percentage of N_(2)

CENGAGE CHEMISTRY ENGLISH-PURIFICATION OF ORGANIC COMPOUNDS AND QUALITATIVE AND QUANTITATIVE ANALYSIS-Single Correct Answer Type
  1. A compound (60 gm) on analysis gave C=24gm H=4gm and O=32gm, its empir...

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  2. An organic compound contains C = 40% , O = 53.34 % and H = 6.60 % . Th...

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  3. A compound contains C=90% and H=10% Empirical formula of the compound ...

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  4. The empirical formula of a compound is CH2O and its vapour density is ...

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  5. The molecular mass of a compound having empirical formula C2H5O is 90....

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  6. A compound contains 38.8%C,16%H, and 45.2%N The formula of the compoun...

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  7. A compound containing 80% C and 20% H is likely to be: C6 H6 C2 H6...

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  8. An organic compound on analysis gave C=42.8%, H=7.2%, andN=50% volume ...

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  9. 0.14 gm of an acid required 12.5 ml of 0.1 N NaOH for complete neutura...

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  10. The empirical formula of a compound is CH2. One mole of this compound ...

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  11. Insulin contains 3.4% suplhur.The minimum molecular mass of insulin is...

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  12. 0.24 g of a volatile gas , upon vaporisation gives 45 mL vapour at NTP...

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  13. Liquid benzene C(6)H(6)) burns in oxygen according to the equation, 2...

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  14. A compound which does not give positive test for nitrogen is: urea ...

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  15. The catalyst used in Kjeldahl's method for the entimation of nitrogen ...

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  16. The concentration of C = 85.45%, and H = 14.44% is not obeyed by the f...

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  17. The prussian blue colour obtained during the test of nitrogen by lassa...

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  18. Which of the following sodium compound is/are formed when as organic c...

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  19. In which of the following compounds, nitrogen cannot be tested by Lass...

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  20. In dumas method for the estimation of nitrogen in an organic compound,...

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