The optical rotation of an optically active compound is `+20^(@)`. The length of tube is `10 cm` and the density of solution is `0.4 gm ml^(-)`. The specific rotation of the compound is: i. `+50^(@)` ii. `+500^(@)` iii. `+5^(@)` iv. `+0.5^(@)`
Text Solution
AI Generated Solution
To find the specific rotation of the optically active compound, we can use the formula for observed rotation:
\[
\alpha_{observed} = [\alpha] \cdot C \cdot L
\]
Where:
- \(\alpha_{observed}\) is the observed rotation (given as \(+20^\circ\)),
...
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