A hydrocarbon `(A)` was found to have vapour density `36`. If forms only a single monochloro substitution product. Suggest `(A)`.

Options

A. a)Iso-pentane
B. b)Neo-pentane
C. c) Cyclo-hexane
D. d)Methyl cyclo-hexane

Explanation

To solve the problem, we need to determine the hydrocarbon (A) that has a vapor density of 36 and forms only a single monochloro substitution product. Here’s the step-by-step solution:

### Step 1: Calculate the Molecular Weight
The vapor density (VD) of a substance is related to its molecular weight (MW) by the formula:
\[ \text{Molecular Weight} = 2 \times \text{Vapor Density} \]
Given that the vapor density is 36, we can calculate the molecular weight:
\[ \text{MW} = 2 \times 36 = 72 \]

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