The keto form of phenol contains:

Options

A. `3 pi, 13 sigma, 4` non-bonding electrons.
B. `3 pi, 9 sigma,4` non-bonding electrons.
C. `3 pi, 9 sigma, 4` non-bonding electrons.
D. `3 pi, 8 sigma, 4` non-bonding electrons.

Explanation

To determine the keto form of phenol and its electron count, we can follow these steps:

### Step-by-Step Solution:

1. **Draw the Structure of Phenol**:
- Phenol consists of a benzene ring with a hydroxyl group (-OH) attached. The structure can be represented as:
```
OH
|
C6H5
```

2. **Identify the Keto Form**:
- The keto form of phenol is formed through tautomerism. In this process, the hydrogen from the hydroxyl group shifts to the adjacent carbon, and a double bond is formed between the carbon and oxygen. The structure of the keto form can be represented as:
```
O
||
C
/ \
C6H4 H
```

3. **Count the Sigma Bonds**:
- In the keto form, we count the sigma bonds:
- Each single bond between atoms counts as one sigma bond.
- The total sigma bonds in the keto form are:
- C-C (5 from the benzene ring)
- C=O (1 from the carbonyl)
- C-H (2 from the hydrogens attached to the carbon)
- Total = 13 sigma bonds.

4. **Count the Pi Bonds**:
- Pi bonds are formed by the overlap of p-orbitals:
- There are 3 pi bonds in the keto form (2 from the double bond in the carbonyl and 1 from the benzene ring).
- Total = 3 pi bonds.

5. **Count the Non-bonding Electrons**:
- Non-bonding electrons are those that are not involved in bonding:
- The oxygen in the keto form has 2 lone pairs (4 electrons).
- Total = 4 non-bonding electrons.

6. **Summarize the Counts**:
- After counting, we summarize:
- Pi Bonds: 3
- Sigma Bonds: 13
- Non-bonding Electrons: 4

7. **Select the Correct Option**:
- Based on the counts, the correct answer is:
- 3 Pi, 13 Sigma, and 4 Non-bonding electrons.

### Final Answer:
The keto form of phenol contains 3 Pi bonds, 13 Sigma bonds, and 4 non-bonding electrons.