The number of isomers of the compound `C_(2)FClBrl` is :

Options

A. 3
B. 4
C. 5
D. 6

Explanation

To determine the number of isomers for the compound \( C_2FClBrI \), we will follow these steps:

### Step 1: Identify the structure of the compound
The compound \( C_2FClBrI \) has two carbon atoms, and it contains four different halogens: fluorine (F), chlorine (Cl), bromine (Br), and iodine (I). The structure can be represented as a double bond between the two carbon atoms, which allows for geometric isomerism (cis-trans isomerism).

### Step 2: Assign priority to the substituents
To determine the geometric isomers, we need to assign priority to the substituents based on the Cahn-Ingold-Prelog priority rules. The priority is assigned based on the atomic number of the atoms directly attached to the carbon atoms:
- For the left carbon, the order of priority is: Cl > Br > F
- For the right carbon, the order of priority is: I > Br > F

### Step 3: Draw the possible isomers
1. **Z isomer (cis)**: Both higher priority groups (Cl and I) are on the same side.
2. **E isomer (trans)**: The higher priority groups (Cl and I) are on opposite sides.

### Step 4: Consider all combinations
Now we can consider all possible combinations of the halogens on the two carbon atoms:
1. **1-bromo-2-chloro-2-fluoro-1-iodoethene** (Z isomer)
2. **1-bromo-2-chloro-2-fluoro-1-iodoethene** (E isomer)
3. **1-bromo-1-chloro-2-fluoro-2-iodoethene** (Z isomer)
4. **1-bromo-1-chloro-2-fluoro-2-iodoethene** (E isomer)
5. **1-bromo-1-fluoro-2-chloro-2-iodoethene** (Z isomer)
6. **1-bromo-1-fluoro-2-chloro-2-iodoethene** (E isomer)

### Conclusion
After considering all the combinations and the geometric isomers, we find that there are a total of **6 isomers** for the compound \( C_2FClBrI \).

### Final Answer
The number of isomers of the compound \( C_2FClBrI \) is **6**.

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