Racemic acid + optically active alcohol having chiral `C` atom `rarr`?
The product will be:

Options

A. Optically active mixtrue
B. Meso compound
C. Diastereomeric mixtrue
D. Racemic mixtrue

Explanation

To solve the question regarding the reaction of racemic acid with an optically active alcohol that has a chiral carbon, we can follow these steps:

### Step 1: Understand the Reactants
- **Racemic Acid**: This is a mixture of equal amounts of two enantiomers (S and R configurations).
- **Optically Active Alcohol**: This alcohol has a chiral carbon and exists as one specific enantiomer (either R or S).

### Step 2: Identify the Configurations
- Let's assume the racemic acid has two enantiomers: one with S configuration (let's denote it as S-acid) and the other with R configuration (R-acid).
- Assume the optically active alcohol has an R configuration.

### Step 3: Perform the Reaction
- When racemic acid reacts with the optically active alcohol, an esterification reaction occurs. This reaction will produce two different esters:
1. The ester formed from the S-acid and the R-alcohol.
2. The ester formed from the R-acid and the R-alcohol.

### Step 4: Analyze the Products
- The two products formed are:
1. S-acid + R-alcohol → S-R ester
2. R-acid + R-alcohol → R-R ester
- The first product (S-R ester) has one chiral center with S configuration and another with R configuration, while the second product (R-R ester) has both chiral centers with R configuration.

### Step 5: Determine the Relationship Between Products
- The two products (S-R ester and R-R ester) are not mirror images of each other; therefore, they are classified as diastereomers.
- Since they are diastereomers, the resulting mixture of products is a diastereomeric mixture.

### Conclusion
The product of the reaction between racemic acid and an optically active alcohol will be a **diastereomeric mixture**.

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