The number of geometrical isomers in `CH_(3)CH=N-OH` is

Options

A. 2
B. 4
C. 5
D. 6

Explanation

To determine the number of geometrical isomers for the compound CH₃CH=N-OH, we can follow these steps:

### Step 1: Identify the structure of the compound
The compound CH₃CH=N-OH can be represented as follows:
- CH₃ (methyl group)
- CH (with a double bond to nitrogen)
- N (double bonded to carbon and single bonded to OH)

### Step 2: Identify the presence of a double bond
In this compound, there is one double bond between the carbon (C) and nitrogen (N) atoms. Geometrical isomerism occurs due to the restricted rotation around double bonds.

### Step 3: Determine the substituents on the double bond
For geometrical isomerism to occur, the double bond must have different substituents on each carbon involved in the double bond. In this case, we have:
- On the carbon atom (C) of the double bond, we have:
- One side: CH₃ (methyl group)
- Other side: N-OH (hydroxylamine group)

### Step 4: Apply the geometrical isomerism formula
The formula to calculate the number of geometrical isomers is:
\[ \text{Number of geometrical isomers} = 2^n \]
where \( n \) is the number of double bonds that can give rise to geometrical isomers.

Here, we have:
- \( n = 1 \) (since there is one double bond)

Now, substituting into the formula:
\[ \text{Number of geometrical isomers} = 2^1 = 2 \]

### Conclusion
Thus, the number of geometrical isomers for the compound CH₃CH=N-OH is 2.

### Final Answer
The number of geometrical isomers in CH₃CH=N-OH is **2**.

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