The smallest aldehyde and its next homologue are treated with `NH_(2)OH` to form oxime. Find out the correct answer out of the following.

Options

A. Two different oximes are formed
B. Three different oximes are formed.
C. Two oximes are optically active.
D. All oximes are optically active.

Explanation

To solve the problem, we need to identify the smallest aldehyde and its next homologue, treat them with hydroxylamine (NH₂OH) to form oximes, and analyze the properties of the resulting oximes.

### Step-by-Step Solution:

1. **Identify the Smallest Aldehyde:**
- The smallest aldehyde is formaldehyde, which has the chemical formula HCHO.

2. **Identify the Next Homologue:**
- The next homologue of formaldehyde is acetaldehyde, which has the chemical formula CH₃CHO.

3. **React with Hydroxylamine:**
- When formaldehyde (HCHO) reacts with hydroxylamine (NH₂OH), it forms an oxime. The reaction can be represented as:
\[ \text{HCHO} + \text{NH}_2\text{OH} \rightarrow \text{C}=\text{N-OH} + \text{H}_2\text{O} \]
- The oxime formed from formaldehyde is hydroxymethyl oxime (H₂C=NOH).

4. **Draw the Structure of the Oxime:**
- The structure of the oxime formed from formaldehyde is:
\[ \text{H}_2C=NOH \]

5. **React Acetaldehyde with Hydroxylamine:**
- When acetaldehyde (CH₃CHO) reacts with hydroxylamine, it also forms an oxime:
\[ \text{CH}_3\text{CHO} + \text{NH}_2\text{OH} \rightarrow \text{C}(\text{CH}_3)=\text{N-OH} + \text{H}_2\text{O} \]
- The oxime formed from acetaldehyde is CH₃C(=NOH)H.

6. **Draw the Structure of the Oxime:**
- The structure of the oxime formed from acetaldehyde can be represented as:
\[ \text{CH}_3C=NOH \]

7. **Analyze the Oximes for Chirality:**
- The oxime from formaldehyde (H₂C=NOH) is not chiral because it has two identical hydrogen atoms attached to the carbon.
- The oxime from acetaldehyde (CH₃C=NOH) can exist in two configurations: E and Z.
- The Z configuration has the CH₃ and OH groups on the same side, making it chiral and optically active.
- The E configuration has the CH₃ and OH groups on opposite sides, making it achiral and optically inactive.

8. **Count the Different Oximes:**
- From the above analysis, we have:
- One oxime from formaldehyde (not optically active).
- Two forms (E and Z) from acetaldehyde (one of which is optically active).
- Therefore, we have a total of three different oximes.

9. **Conclusion:**
- The correct answer is that there are three different oximes formed, and only one of them is optically active.

### Final Answer:
The correct option is **three different oximes, with one being optically active.**